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hoa [83]
3 years ago
10

What is the best approximation for the input value when f(x)=g(x)?

Mathematics
2 answers:
Lostsunrise [7]3 years ago
8 0

Answer:

x=0 and x=1.

Step-by-step explanation:

If we have to different functions like the ones attached, one is a parabolic function and the other is a radical function. To know where f(x)=g(x), we just have to equalize them and find the solution for that equation:

x^{2}=\sqrt{x} \\(x^{2} )^{2}=(\sqrt{x} )^{2}\\x^{4}=x\\x^{4}-x=0\\x(x^{3}-1)=0\\

So, applying the zero product property, we have:

x=0\\x^{3}-1=0\\x^{3}=1\\x=\sqrt[3]{1}=1

Therefore, these two solutions mean that there are two points where both functions are equal, that is, when x=0 and x=1.

So, the input values are  x=0 and x=1.

gavmur [86]3 years ago
7 0

Answer:1.5

Step-by-step explanation: Got it correct on edge.

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Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)​
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The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Step-by-step explanation:

Given polynomials are:

(x^3+3x^2+1)\\and\\(3x^2+6x-2)

In order to multiply both polynomials, we will use the distributive property

So,

= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2

Combining like terms

=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2

Hence,

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Keywords: Polynomials, variables

Learn more about polynomials at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

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