Answer:
see below for the graph
Step-by-step explanation:
The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.
Here's one way to get there.
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Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.
Now, it is ...
f(x) = |x| -1
We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.
Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...
g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5
This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:
x = -(5/3)|y| +5
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<em>Comment on this answer</em>
Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.
Answer:
regular pay per hour =9.15
overtime pay per hour =13.725
Answer:
eqn of line
3x-4y=-16
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
<u>Given points:</u>
<u>Let's calculate it's equation:</u>
- y = mx +b
- m = (4 + 11)/(6 +3) = 15/9 = 5/3
- y = 5/3x + b
- -11 = 5/3*(-3) + b ⇒ b = -11 + 5 = -6
- y = 5/3x - 6
<u>The given line:</u>
Compared, the lines have different slope (5/3 vs 32) but same y- intercept (-6), so both pass through the point of (0, -6). y= 32x - 6 has greater rate of change.