Answer:
Step-by-step explanation:
g(t)=t^2 - t
f(x) = (1 + x)
g(f(x)) = f(x)^2 - f(x)
g(f(x)) = (x + 1)^2 - x - 1
g(f(0)) = (0 +1)^2 - x - 1
g(f(0)) = 1 - 1 - 1 = -1
================================
f(x) = 1 + x
f(g(t)) = 1 + g(t)
f(g(t)) = 1 + t^2 - t
f(g(0)) = 1 + 0 - 0
f(g(0)) = 1
The answer I'm getting is 0.
Answer:
C) 32 * 2**1/2
Step-by-step explanation:
For rectangle P = L + W = 24 but L = 2W so
2W + W = 24
3W = 24
W = 8 and L = 2W = 16
A = L * W = 16 * 8 = 128
SO for the square with the same area
A = L * L = 128
L**2 = 128
L = 8 * 2**1/2
P = 4L = 32 * 2**1/2
Answer:
14r+11
Step-by-step explanation:
3+5r+9r+8
=11+14r
F(x) = <span>x^2+3x+8
now, the pending of the tangent line is d/dx f(x)
f'(x) = 2x + 3
now, we need know when the pending is increasing.
so
</span>2x + 3> 0
solving
x>-3/2
The interval over which the function f(x)= x^2+3x+8 is <span>increasing is (-3/2,+</span>∞<span>)</span><span>
</span>
Answer:
35,000^10
Step-by-step explanation:
multiply 7,000 and 50 first (350,000) then erase the last 0 (35,000) then raise it to 10 (35,000^10)
