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Marysya12 [62]
3 years ago
11

In ΔIJK, j = 540 inches, ∠I=54° and ∠J=69°. Find the area of ΔIJK, to the nearest square inch.

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

105963

Step-by-step explanation: delta math

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Which interval notation accurately represents the domain?
Sauron [17]

Answer:

the 1st one

next

the 3rd one

Step-by-step explanation: edg 2020

7 0
3 years ago
The diameter of Jupiter is 142.984 Km. The surface area of Saturn is 59.9% the surface area of Jupiter. What is Saturn's diamete
Otrada [13]
Suppose that both planets are spherical. radius of Saturn =142984/2=71,492

Area of Jupiter = 4πr² ==>4π(71,492)² =6.4228 x 10^10

Area of Saturn ==>(6.4228 x 10^10)x(0.599) ==>3,84726 x 10^10

Radius of Saturn = 4πr² =3,84726 x 10^10==> r²=3,0219 x 10^10
and r √(,0219 x 10^10) = 174.000 km & D = 384,000 km
5 0
3 years ago
How many 2/3's are in 4/5
zhannawk [14.2K]

Step-by-step explanation:

4/5 + 2/3 = 2215 = 1 715 ≅ 1.4666667. Spelled result in words is twenty-two fifteenths (or one and seven fifteenths).

5 0
3 years ago
Read 2 more answers
What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the
marishachu [46]
The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

\sum_{i=1}^n x_i = n \bar x

So if the average of all 92 is 7 the sum of those is 92 \times 7

The average of the last two is 7.2 so their sum is 2 \times 7.2

That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

 \dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556 cm



7 0
3 years ago
In a manufacturing process, a random sample of 36 bolts has a mean length of 3 inches with a standard deviation of .3 inches. Wh
Liula [17]

The 99 percent confidence interval for the true mean length of the bolt is CI = (2.8712, 3.1288)

<h3>How to find the confidence interval?</h3>

Confidence Interval is used to tell us the degree of certainty or uncertainty that is existent in a sampling method.

The general formula for confidence interval is;

CI = x' ± z(s/√n)

where;

x' is sample mean

z is z-score at confidence level

s is sample standard deviation

n is sample size

We are given;

sample size; n = 36

Sample mean; x' = 3 inches

standard deviation; s = 0.3 inches

confidence level = 99%

z at 99% CL = 2.576

Thus;

CI = 3 ± 2.576(0.3/√36)

CI = 3 ± 0.1288

CI = (2.8712, 3.1288)

Read more about Confidence Interval at; brainly.com/question/17097944

#SPJ1

3 0
1 year ago
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