Answer:
Step-by-step explanation:
<h3>Given</h3>
<h3>To find</h3>
- log6 15 in terms of a and b
<h3>Solution</h3>
<u>Rewrite the given</u>
- log9 2 = a ⇒ log2/log9 = a ⇒ 1/2*log2/log3 = a ⇒ log3 = 1/2*log2/a
- log5 4 = b ⇒ log4/log5 = b ⇒ log5 = 2*log2/b
<u>Rewriting the log6 15:</u>
- log6 15 = log15/log6= (log 5 + log3)/(log2 + log3)
<u>Substitute as follows:</u>
- (log 5 + log3)/(log2 + log3) =
- (2*log2/b + 1/2*log2/a)/(log2 + 1/2*log2/a) =
- (2/b + 1/(2a))/(1 + 1/(2a)) =
- (4a + b)/2ab ÷ (2a + 1)/2a =
- (4a + b)/(2ab + b)
Answer:
9
Step-by-step explanation:
i hope this helps!
Answer:
Natalie's age is 14
Sasha's age is 17
Step-by-step explanation:
Let
Sasha's age be "s", and
Natalie's age be "n"
<u>Sum of Sasha and Natalie is 31:</u>
s + n = 31
<u>Twice Natalie is 11 more than Sasha:</u>
2n = s + 11
We ca solve this equation for s first:
s = 2n - 11
We put this into first equation and solve for n first:
s + n = 31
2n - 11 + n = 31
3n = 31 + 11
3n = 42
n = 42/3 = 14
Natalie's age is 14
Also, s = 2n - 11
s = 2(14) - 11
s = 28 - 11
s = 17
Sasha's age is 17
(x-5)(x+7).
explanation:
(x-5)(x+7)=0
<=> x-5=0 or x+7=p
<=> x=5 or x=-7
