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Vladimir79 [104]
3 years ago
11

Fred is baking cookies for a school sale. It takes 3/4 cups of sugar to make on batch of cookies how many cups of sugar does he

need to make 9 batches
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer:

6 3/4 cups.

Step-by-step explanation:

Multiply 3/4 by 9.

<em>Hope this helps!</em>

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1

Step-by-step explanation:

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According to a recent​ poll, 25​% of adults in a certain area have high levels of cholesterol. They report that such elevated le
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Answer:

The answer is below

Step-by-step explanation:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\for\ a \ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\where\ x=raw\ score,\mu=mean, \sigma=standard deviation

Given that n = 49, μ = 260 mg/dL, σ = 35 mg/dL

a) For x < 210:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{210-260}{35/\sqrt{49} } =-10

From the normal distribution table, P(x < 210) = P(z < -10) = 0.0001

b) For x > 205:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{205-260}{35/\sqrt{49} } =-11

For x < 215:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{215-260}{35/\sqrt{49} } =-9

P(205 < x < 215) = P(-11 < z < -9) = P(z < -9) - P(z < -11) = 0.0001 - 0.00001 = 0.00009

c) For x < 200:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{200-260}{35/\sqrt{49} } =-12

From the normal distribution table, P(x < 200) = P(z < -12) = 0.00001

d) For x > 222:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{222-260}{35/\sqrt{49} } =-7.6

From the normal distribution table, P(x > 200) = 1 - P(z < -12) = 1 - 0.0001 = 0.9999

7 0
3 years ago
PLEASE HELP!!!
AlekseyPX

Answer:

D.

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = \frac{m(b) - m(a)}{b - a}

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = \frac{4 - (-12)}{2 - (-2)}

= \frac{16}{4}

Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = \frac{n(b) - n(a)}{b - a}

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = \frac{6 - (-6)}{2 - (-2)}

= \frac{12}{4}

Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = \frac{q(b) - q(a)}{b - a}

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = \frac{-12 - (-4)}{2 - (-2)}

= \frac{-8}{4}

Average rate of change = -2

✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = \frac{p(b) - p(a)}{b - a}

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = \frac{-4 - 12}{2 - (-2)}

= \frac{-16}{4}

Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

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Answer:

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