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Amiraneli [1.4K]
3 years ago
15

What is y+7/7y÷3y^2+21y/14y−5 simplified?

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
This becomes...........

[(y+7)/7y] x [(14y-5)/(3y^2+21y)]= [(y+7)/7y] x [(14y-5)/3y(y+7)]= [1/7y] x [(14y-5)/3y]= [(14y-5)/21y]


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Identify the correct corresponding parts
andrey2020 [161]

Answer:

The correct corresponding part is;

\overline {CB} ≅ \overline {CD}

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment \overline {CA} is congruent to \overline {CE} ( \overline {CA} ≅ \overline {CE})

Segment \overline {CB} is congruent to \overline {CD} ( \overline {CB} ≅ \overline {CD})

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment \overline {AB} is congruent to \overline {DE} (\overline {AB} ≅ \overline {DE}) by CPCTC

Segment \overline {AE} bisects \overline {BD}

Segment \overline {BD} bisects \overline {AE}

Therefore, the correct option is \overline {CB} ≅ \overline {CD}

3 0
3 years ago
83. 6 in a complex number
grin007 [14]

Answer:

83.6 is a real number

Step-by-step explanation:

Since 83.6 83.6 is a real number, it is the real part (a) of the complex number a+bi a + b i . A real number does not contain any imaginary parts, so the value of b b is 0 0 . The answer is 83.6+0i 83.6 + 0 i

5 0
4 years ago
Isosceles JAM has convex angle M. JM=35,MA=4n+3, angle J=14w-1, and angle m=98 Find n. Find w. Find the perimeter of JAM
Lena [83]

Answer:

n = 8, w = 3 and perimeter = 122.83 units.

Step-by-step explanation:

Let the angle M is the angle between the equal sides of isosceles JAM.

So, JM = MA

⇒ 35 = 4n + 3

⇒ 4n = 32

⇒ n = 8 (Answer)

Now, if ∠ J = 14w - 1 and ∠ M = 98°, then

2(14w - 1) + 98 = 180

⇒ 2(14w - 1) = 82

⇒ 14w - 1 = 41

⇒ w = 3 (Answer)

Now, draw a perpendicular bisector on JA from vertex M and it meets JA at P say.

So, Δ MPJ will be a right triangle with ∠ J = (14w - 1) = 41° {Since w = 3}

Hence, \cos 41 = \frac{JP}{JM} = \frac{JP}{35}

⇒ JP = 35 cos 41 = 26.415

So, JA = 2 × JP = 52.83  

So, the perimeter of Δ JAM is = 35 × 2 + 52.83 = 122.83 units (Answer)

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4 years ago
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