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Amiraneli [1.4K]
3 years ago
15

What is y+7/7y÷3y^2+21y/14y−5 simplified?

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
This becomes...........

[(y+7)/7y] x [(14y-5)/(3y^2+21y)]= [(y+7)/7y] x [(14y-5)/3y(y+7)]= [1/7y] x [(14y-5)/3y]= [(14y-5)/21y]


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