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Amiraneli [1.4K]
4 years ago
15

What is y+7/7y÷3y^2+21y/14y−5 simplified?

Mathematics
1 answer:
Soloha48 [4]4 years ago
6 0
This becomes...........

[(y+7)/7y] x [(14y-5)/(3y^2+21y)]= [(y+7)/7y] x [(14y-5)/3y(y+7)]= [1/7y] x [(14y-5)/3y]= [(14y-5)/21y]


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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
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  2. [√Radical] (Parenthesis} Add/Subtract:                                                         \displaystyle d = \sqrt{(8)^2+(-6)^2}
  3. [√Radical] Evaluate exponents:                                                                     \displaystyle d = \sqrt{64+36}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{100}
  5. [√Radical] Evaluate:                                                                                       \displaystyle d = 10
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