What is y+7/7y÷3y^2+21y/14y−5 simplified?

1 answer:

6 0

This becomes...........

[(y+7)/7y] x [(14y-5)/(3y^2+21y)]= [(y+7)/7y] x [(14y-5)/3y(y+7)]= [1/7y] x [(14y-5)/3y]= [(14y-5)/21y]

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