I'm not sure if that is supposed to be 7 or -7
If it's -7:
1<2n-5<-7
+5 +5 +5 Add 5 to all parts of the inequality get 2n by itself
6<2n<-2
/2 /2 /2 Divide all parts by 2 to isolate the variable
3
Answer:
1. 4x - 29=11
2. (3x - 4) (2) = 46
3. 3/5x + 8 = 50
4. The difference of 51 and the sum of x and 5.
5. The product of 3 and y minus eight.
Step-by-step explanation:
X+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10+x+11+x+12/12
12x+78/12 = 132 times 12 is
12x+78 = 1,548 minus 78
12x = 1,506 divide by 12
x = 125.5 I believe is the answer, sorry if it is wrong
Answer:
38 mpg
Step-by-step explanation:
Initial efficiency = 39 mpg
Initial speed = 40 mph
Final speed = 50 mph
The efficiency drop between 40 mph and 50 mph is given by:
![E_d = 0.1 \frac{mpg}{mph}*\Delta V](https://tex.z-dn.net/?f=E_d%20%3D%200.1%20%5Cfrac%7Bmpg%7D%7Bmph%7D%2A%5CDelta%20V)
The total efficiency drop from 40 to 50 mph is:
![E_d = 0.1 \frac{mpg}{mph}*(50-40)mph\\E_d = 1\ mpg](https://tex.z-dn.net/?f=E_d%20%3D%200.1%20%5Cfrac%7Bmpg%7D%7Bmph%7D%2A%2850-40%29mph%5C%5CE_d%20%3D%201%5C%20mpg)
Therefore, the efficiency at 50 mph is:
![E_{50} = E_{40} -E_d\\E_{50} = 39 -1\\E_{50} = 38\ mpg](https://tex.z-dn.net/?f=E_%7B50%7D%20%3D%20E_%7B40%7D%20-E_d%5C%5CE_%7B50%7D%20%3D%2039%20-1%5C%5CE_%7B50%7D%20%3D%2038%5C%20mpg)