Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
First, find the slope of the line using the formula for slope:
m = (y2 - y1) / (x2 - x1)
m = (4 - (-2)) / (-3 - 2) = -6/5
Then, use the point-slope formula using a point that you were given and the slope that you calculated.
y - y1 = m(x - x1)
y - 4 = (-6/5)(x + 3)
Then, simply get y alone.
y = (-6/5)x + 2/5
<span><span>(<span><span>8x</span>+7</span>)</span>*<span>(<span><span>8x</span>+7</span>)</span></span>*<span>(<span><span>8x</span>+7</span><span>)
</span></span><span>(<span><span>8x</span>+7</span>)</span><span>(<span><span><span>64<span>x^2</span></span>+<span>112x</span></span>+49</span><span>)
</span></span><span><span><span><span><span><span><span>(<span>8x</span>)</span><span>(<span>64<span>x^2</span></span>)</span></span>+<span><span>(<span>8x</span>)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(<span>8x</span>)</span><span>(49)</span></span></span>+<span><span>(7)</span><span>(<span>64<span>x^2</span></span>)</span></span></span>+<span><span>(7)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(7)</span><span>(49)
</span></span></span><span><span><span><span><span>512<span>x^3</span></span>+<span>896<span>x^2</span></span></span>+<span>392x</span></span>+<span>448<span>x^2</span></span></span>+<span>784x</span></span>+<span>343
</span>Answer:
<span><span><span>512<span>x^3</span></span>+<span>1344<span>x^2</span></span></span>+<span>1176x</span></span>+<span>343</span>
The unit rate in dollars per ounce would be $403.90.
Hope this helps! :D
Answer:
37.5% that is the answer
Step-by-step explanation:
