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Tasya [4]
3 years ago
9

Ms. Sims is putting away 22 books. She can put them on the table in stacks of 10 or as single books. What are the different ways

Ms. Sims can put away the books?
Mathematics
2 answers:
Rashid [163]3 years ago
8 0

Answer:

1)10+10+1+1=22

2)10+1+1+1+1+1+1+1+1+1+1+1+1=22

Step-by-step explanation:

Mrs. Sims has to put 22 books.

She can either put them in stacks of 10 or arrange them as single book(single stack).

There could be two ways in which she could arrange the books.

First way:

She could arrange the books in two stacks of 10 books (2\times10=20 and the remaining two books can be arranged as single books.

So, the arrangement is 10+10+1+1=22

Second way:

She could arrange books in one stack of 10 books and and remaining twelve books can be arranged as single books.

So, the arrangement is 10+1+1+1+1+1+1+1+1+1+1+1+1=22

sesenic [268]3 years ago
3 0
She can put them on an empty shelf all together or individually sort them in there proper order
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Step-by-step explanation:

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In this type of math equation, you have to multiply all members from the first part with the second part.

Expanded:

e \times e+e \times (-5)+e \times e+e \times 3

simplified:

{2e}^{2}  + ( - 2e)

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3 years ago
Izzy's Frozen Treats sells both frozen yogurt and frozen custard by the ounce. Last week, Marco noticed that a 3-ounce cup of fr
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Answer:

A. Frozen yogurt

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The frozen yogurt costs less than the frozen custard, even though you get the same amount (3 ounces)

No matter how much money Marco has, he would be able to buy more of the frozen yogurt because it has a cheaper unit rate.

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8 0
3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
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