Answer:
c) The equation to find the price of each shrub is $53.50 = 4 p + $17.50
The cost of 1 shrub = p = $ 9.00
Step-by-step explanation:
The total number of shrubs purchased = 4
The price paid for potting soil = $17.50
The total bill of purchase = $53.50
Let us assume the cost of 1 shrub = $p
The total amount spent of 4 shrubs = 4 x ( The price of each shrub) = 4 p
TOTAL BILL = The amount paid for 4 shrubs + AMOUNT paid for SOIL
⇒ $53.50 = 4 p + $17.50
Now. solving for p, we get:
53.50 - 17.50 = 4 p
or, 3 6 = 4 p
or, p = 36/4 = 9
or, p = 9
Hence, the cost of each shrub = $9
Answer:
6
Step-by-step explanation:
Any circle in the form

Where r^2 is the radius squared, so


Answer:
Yeah she is right but its kinda hard to know wahat u want
Step-by-step explanation:
Let's assume
It started in 2000
so, t=0 in 2000

we can use formula

we can plug value

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million
so, at t=2005-2000=5
P(t)=7.3 million
we can plug value and then we can solve for r


now, we can plug back

now, we have
P(t)=1 billion =1000 million
so, we can set it and then we can solve for t


approximately

Year is 2000+192
year is 2192................Answer
She has a total of 170 cubes
170/10=17 trains