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3 years ago

10

the probability of rolling a number less than 3 on a number cube is 2/6. Jennifer rolls 60 times. how many times should Jennifer

expect to roll a number less than 3

1 answer:

saveliy_v [14]3 years ago

7 0

Answer:23

Step-by-step explanation:

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Classify the following triangle as acute, obtuse, or right.

liubo4ka [24]

D. None of these.

Equilateral is the only triangle that has all the sides that are equal to each other. Hope this helped you :)

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2 years ago

Read 2 more answers

In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? AB ≅

torisob [31]

Answer:

Step-by-step explanation:

For any quadrilateral to be a parallelogram

i) either both the pairs of opposite sides must be equal

ii) Both the pairs of opposite sides must be parallel

iii) Opposite pairs of angles must be equal

iv) Diagonals must bisect each other.

v) A pair of opposite sides must be parallel and equal

Here we are already given that AB || CD

So either we should be given that AD || BC

or we must be given that AB = CD

Here it is given AB = CD as an option.

So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.

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2 years ago

Chen has 4 pizzas to share with his friends. If each person will eat 2/3 of a pizza,how many people can share the pizzas?

sweet-ann [11.9K]

Answer:6 people

Step-by-step explanation: divide 4 by 2/3

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3 years ago

Which of the following statement is true? Select all that apply.

jenyasd209 [6]

Answer:

1 and 2 are the answers i think

Step-by-step explanation:

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3 years ago

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

<em><u>The question is</u></em>

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

so

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

5 0

3 years ago