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Hypotenuse = 9cm^2+ 13cm^2
=81 +169
=250
= \{250}(find the square root)
=16cm^2(hypotenuse)
Answer:
Step-by-step explanation:
A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?
This is a circle inscribed in an equilateral triangle with side s.
If you are asking for the perimeter of PQR, it is 3s.
If you are asking for the perimeter of OQR, it is (3+23–√3)s
Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.
(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s
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Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given


Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.

This gives:

Collect Like Terms


Solve for P


This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:



<em>Hence, the equilibrium quantity is 26.4</em>
The statement Perpendicular line intercept at 90 degree angle is true.