Answer:
D
Step-by-step explanation:
The two graphs are reflections of each other in the y-axis
If one is f(x), other is f(-x)
c^x = b^(-x)
c = b^-1
c = 1/b
The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
This a dang easy question. Ask yourself,what is the sentence about?
