Consider the closed region

bounded simultaneously by the paraboloid and plane, jointly denoted

. By the divergence theorem,

And since we have

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have




Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by

, we have

Parameterize

by


which would give a unit normal vector of

. However, the divergence theorem requires that the closed surface

be oriented with outward-pointing normal vectors, which means we should instead use

.
Now,



So, the flux over the paraboloid alone is
Answer:
9/2
distribute the value of x,y, and z, on the given questions, and then you do multiplication, next addition, lastly lowest term.
Answer:
A: 22
Step-by-step explanation:
2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.
I think that is is 8.3, but I could be incorrect!