Why is this not a function? (picture attached ^) <br><br> YOU WILL GET BRAINLEST FAST!

Multiply and simplify. 2x^4yx⋅6xy^2z^3

Mrac [35]

The answer is letter a

4 0

3 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

(-w-6)/(w^2+4w-12), how do i write this into simplest form?

PIT_PIT [208]

First factorise the top = -(w+6)
The first factorise the bottom: (w^2 + 4w -12) = (w+6) (w-2)
Therefore the two (w+6) cancels out and you are left with -1 / w-2

7 0

3 years ago

Jack and Diane participated in a weight loss program jack lost 6 pounds per Month for seven months Diane lost 4 pounds per month

Korolek [52]

Answer:

Step-by-step explanation:

your welcome

5 0

2 years ago

Which line has an equation of y=-5x+4 in slope-intercept form?

tino4ka555 [31]

You can figure the line for each pair of points, or you can try the points in the equation you have and see which are on the line.

First answer: x=1, y=-5×1 +4 = -1 . . . not 9. (1, 9) is not a point on the line

Second answer: x=2, y=-5×2 +4 = -6 . . . not -14. (2, 14) is not a point on the line

Third answer: (see the calculation for the first answer) . . . -1 ≠ 1. (1, 1) is not a point on the line

Fourth answer: (see the calculation for the second answer) We know that (2, -6) is on the given line. Checking (4, -16), we find it is as well.

The appropriate choice is the 4th answer:

... a line passing through the points (2, -6) and (4, -16)

4 0

3 years ago

Read 2 more answers

Why is this not a function? (picture attached ^) YOU WILL GET BRAINLEST FAST!