Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
Answer:
111°
Step-by-step explanation:
Let the centre of the circle be C
mRQ=157 (marked)
The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92
All the arc measure add up to 360 so:
mSQ+mRQ+mSR=360
mSQ+157+92=360
mSQ=360-249=111
Answer:
h(t) = -16t(t-6)
h(2) = 128
Step-by-step explanation:
h(t) = -16t² + 96t
h(t) = -16t(t-6)
t = 3
h(2) = -16(2)(2 - 6)
h(2) = 128
35.75
explanation-
3.90 ph x 7.5 hours = 29. 25
plus the gas can 6.50
29.25+6.50= 35.75
The sum is 45577788999000866;33sorry
