Raj reads 7\12 of his book before dinner and another 2\12 of his book after dinner
1 answer:
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Sa= bw+hw+lw+
(2)
SA=(12*4)+(16*4)+(20*4)+(
)
SA= 28+64+80+(6*16*2)
SA=28+64+80+(96*2)
SA=28+64+80+192
SA=364
SA=(12*4)+(16*4)+(20*4)+(
SA= 28+64+80+(6*16*2)
SA=28+64+80+(96*2)
SA=28+64+80+192
SA=364
Answer: 20 mph
Explanation:
Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):
In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:
(1)
During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:
(2)
So we have two equations with two unknown variables. From (1), we get
Substituting into eq.(2)
So, the speed of the wind was 20 mph.