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melamori03 [73]
3 years ago
15

Use the figure to answer the following question.

Mathematics
1 answer:
insens350 [35]3 years ago
8 0

Answer:

The answer to the equation was c so yes you are right:)

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The number of seats in a row has been increased at a rectangular-shape movie theater after renovation so that it is now five mor
Damm [24]

Let the number of rows be = r

Let the number of seats per row be = s

we know that the number of seats is 126.

So, s\times r=126    ..... (1)

As given, there are five more seats per row than the number of rows, so we can say that:

s=r+5

Putting this in equation (1)

(r+5)*r=126

r^{2}+5r=126

r^{2}+5r-126=0

r^{2}+14r-9r-126=0

(r+14)(r-9)=0

r=-14 and r=9 (neglecting the negative value) we get r=9

And s=r+5

so, s =9+5=14

Hence, there are 5 rows and 14 seats per row.

4 0
4 years ago
Find the values of a and b that make the quadrilateral a parallelogram.
Yuri [45]

Step-by-step explanation:

both halves of a diagonal must be equal.

so,

8b - 30 = 6b + 6

2b = 36

b = 18

and

9a - 13 = 5a + 5

4a = 18

a = 18/4 = 4.5

5 0
2 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
Y=x^2-25 is it linear?
Svetllana [295]

Answer:

yes it is i think

7 0
3 years ago
Read 2 more answers
if the farm needs to pack 12,70,224 litchis in boxes that hold 144 litchis ,how many boxes would be required .​
uysha [10]

For this, we will divide 1,270,224 by 144.

1,270,224 ÷ 144 = 8,821.

For this result, we can conclude that the number of boxes required to pack 1,270,224 litchis is 8,821 boxes.

7 0
3 years ago
Read 2 more answers
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