We first integrate the expression to find the oil leaked since we have an expression for leakage rate.
Integrating:
O(t) = -10000exp(-0.2t); substituting t = 10
O(t) = -1,353 gallons
1,353 gallons of oil leak out in the first 10 seconds.
125.
16 (10 and 6) divided by 100 is 6.25. Times two is 12.5. (For 200) times 10 for 10 marbles.
