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3 years ago

Hello can anyone help me with these problems please and ty

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

12. x= 4

13. x= 4

14. x= -1

Check the steps in the picture above

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The volleyball team and the wrestling team at Stamford High School are having a joint car wash today,

Sedbober [7]

Answer:

Money raised by each team = 94 + 11 = $105

Number of cars washed = 11

Step-by-step explanation:

Money already present with volleyball team = $50

Money raised by washing each car by volleyball team = $5

Let the number of cars washed = $x$

Money raised by washing cars = $5 $x$

Money already present with volleyball team = $94

Money raised by washing each car by volleyball team = $1

Money raised by washing cars = $1 $x$ = $ $x$

Given that, both the teams have raised same amount of money:

$50+5x=94+x\\\Rightarrow 44=4x\\\Rightarrow x=11$

Money raised by each team = 94 + 11 = $105

Number of cars washed = 11

4 0

3 years ago

FOR 15 POINTS Determine whether each given value of h makes the inequality 4h + 13 ≤ −7 true. Select Yes or No for each value.

Norma-Jean [14]

Answer:

Yes, no, yes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If f(x) = 3^x + 10x and g(x) = 2x - 4, find (f + g)(x)

allsm [11]

Answer:

3^x + 12x -4

Step-by-step explanation:

f(x) = 3^x + 10x

g(x) = 2x - 4,

(f + g)(x) = 3^x + 10x + 2x - 4

Combine like terms

= 3^x + 12x -4

6 0

3 years ago

Read 2 more answers

I NEED THIS ASAP, PLEASE HELP!!!

WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0

4 years ago

Find the range of the function f(x)=5-4x given the domain = {-1,0,1}

kondor19780726 [428]

Answer:

I don't get what you are trying to say I think you need to put it in better understanding

7 0

3 years ago