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iVinArrow [24]
3 years ago
11

Can anyone help you pleased :)

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

c

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

(h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (- 2, - 4 ), then

f(x) = a(x + 2)² - 4

To find a substitute any other point on the graph into the equation

Using (- 4, 0 )

0 = a(- 4 + 2)² - 4 ( add 4 to both sides )

4 = 4a ( divide both sides by 4 )

a = 1

Thus

f(x) = (x + 2)² - 4 → c

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What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
spayn [35]

Answer: 6,8 and 10

Step-by-step explanation:

To find the length , all we need to find is the distance between each point ,

the formula for calculating distance between two points is given by :

D = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

Let the points be :

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Calculating the length AB , we have

D1 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

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Calculating the length AC , we have

D2 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

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Calculating the length BC , we have

D3 = \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}

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3 years ago
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Step-by-step explanation:

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~kaikers
5 0
4 years ago
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