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iVinArrow [24]
3 years ago
11

Can anyone help you pleased :)

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

c

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

(h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (- 2, - 4 ), then

f(x) = a(x + 2)² - 4

To find a substitute any other point on the graph into the equation

Using (- 4, 0 )

0 = a(- 4 + 2)² - 4 ( add 4 to both sides )

4 = 4a ( divide both sides by 4 )

a = 1

Thus

f(x) = (x + 2)² - 4 → c

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-2(1-3x)=22-3(x-13) please help
Alex17521 [72]

Let's solve this problem step by step.

−2(1−3x)=22−3(x−13)

Step 1: Simplify both sides of the equation.

(−2)(1)+(−2)(−3x)=22+(−3)(x)+(−3)(−13)(Distribute)

−2+6x=22+−3x+39

6x−2=(−3x)+(22+39)(Combine Like Terms)

6x−2=−3x+61

Step 2: Add 3x to both sides.

6x−2+3x=−3x+61+3x

9x−2=61

Step 3: Add 2 to both sides.

9x−2+2=61+2

9x=63

Step 4: Divide both sides by 9.

9x/9=63/9

So, the answer to this problem is x=7.

3 0
3 years ago
2x - 4y = 12, 2x + 7y = 1<br><br> Can you help me solve for x and y?
Sedaia [141]
(X,y)=(4, -1)


Hope this helps! :))
6 0
3 years ago
The coordinates of the vertices of a quadrilateral are (8, 11) (11, 7) (8, 3) (2, 3). What is the area, in square units, of the
disa [49]

Check the picture below.

so the quadrilateral is really just a parallelogram below a triangle, so let's simply get the area of each and sum them up.

\stackrel{\textit{\Large Areas}}{\stackrel{parallelogram}{(6)(4)}~~ + ~~\stackrel{triangle}{\cfrac{1}{2}(6)(4)}}\implies 24~~ + ~~12\implies 36

6 0
2 years ago
Use the Pythagorean Theorem to find x.
Anarel [89]

Answer:

x = \sqrt{245}

Step-by-step explanation:

<u>Step 1:  Find the hypotenuse</u>

<u />a^2 + b^2=x^2

14^2+7^2=x^2

245=x^2

\sqrt{245} =x

Answer:  x = \sqrt{245}

6 0
3 years ago
Read 2 more answers
M&lt;KGH=x+161,m&lt;FGK=x+41,and m&lt;FGH=180° Find x
Butoxors [25]

Answer: x = -11   ∠FGK = 30°   ∠KGH = 150°

<u>Step-by-step explanation:</u>

∠FGK + ∠KGH = ∠FGH    <em>Segment Addition Postulate</em>

x + 41 + x + 161 = 180       <em>Substitution</em>

2x + 202 = 180  <em>               Simplify (added like terms)</em>

2x = -22                            <em>Subtraction Property of Equality</em>

x = -11                               <em>Division Property of Equality</em>

 

∠FGK = x + 41     = (-11) + 41    = 30

∠KGH = x + 161   = (-11) + 161   = 150

4 0
3 years ago
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