Answer:
Modern technology has developed
Explanation:
The development of technology may draw upon many fields of knowledge, including scientific, engineering, mathematical, linguistic, and historical knowledge, to achieve some practical result. ... For example, science might study the flow of electrons in electrical conductors by using already-existing tools and knowledge.
Answer:
Liam could
1) Change the password
Be sure to change the password to a "strong" one (containing lots of characters, numbers, symbols) so that way the password would be difficult to guess.
2) Avoid logging onto social media on public computers or WiFi connections.
Using public WiFi leaves you vulnerable to someone accessing your information through Internet traffic. If you do use public computers, just make sure to log out.
3) Avoid giving out account information to friends and avoid opening suspicious links and emails.
Opening suspicious links or emails could allow malware to infect your computer the moment you open them. Friends can unknowingly share these links that are designed to steal information.
I hope this helped <3 please lmk if there's anything more to add.
Answer:
Thermal Compound/Thermal Grease
Explanation:
Thermal compound, also known as thermal paste and thermal grease, is a material used to fill the microscopic gaps between a computer's CPU and its heat sink. Thermal compound significantly increases the heat sink's ability to cool the CPU, allowing the CPU to run at a higher speed and improve system performance.
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.
