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2 years ago

Please help I need it please please please

Mathematics

1 answer:

Marysya12 [62]2 years ago

8 0

Answer:

the first i think

Step-by-step explanation:

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1/2 pound : 5 days find the unit rate

juin [17]

Answer:

0.1

Step-by-step explanation:

To set this question up:

1/2 / 5

To solve this turn 5 into 5/1. Then multiply by the reciprocal. (1/5) 1/2 times 1/5 is 0.1

8 0

3 years ago

Read 2 more answers

Suppose 1/4 of students in your school

DedPeter [7]

Answer: 60 students i think

5 0

3 years ago

The following represents the probability distribution for the daily demand of microcomputers at a local store. Demand Probabilit

konstantin123 [22]

Answer:

The correct answer is 2.2.

Step-by-step explanation:

The following represents the probability distribution for the daily demand of microcomputers at a local store:

Demand Probability

f(0)= .1

f(1)= .2

f(2)= .3

f(3)= .2

f(4)= .2.

Expectation of a discrete probability function f of the random variable x is given by ∑ x × f(x).

Thus the expected value of demand is given by

0.1 × 0 + 0.2 × 1 + 0.3 × 2 + 0.2 × 3 + 0.2 × 4 = 2.2.

The expected daily demand is 2.2.

8 0

3 years ago

PLEASE HELP ASAP!!!!!

Wittaler [7]

Answer:

$sec(x)$

Step-by-step explanation:

$cos(x)+cos(x)tan^2(x)$

Multiply cos(x) by 1:

$cos(x)*1+cos(x)tan^2(x)$

Factor out cos(x):

$cos(x)(tan^2(x)+1)$

Apply the pythagorean identity ( $tan^2(x)+1=sec^2(x)$ ):

$cos(x)sec^2(x)$

Rewrite $sec^2(x)$ :

$cos(x)(\frac{1}{cos(x)})^2 \\cos(x)\frac{1}{cos^2(x)}$

Cancel cos(x):

$\frac{1}{cos(x)}$

Rewrite:

$sec(x)$

5 0

4 years ago

I need help with trigonometry Again..

tigry1 [53]

Answer: C. - √2

Step-by-step explanation:

Given requirements from the question

Find the exact value of sec 135°

Convert into common trigonometric expression

sec = secant

secx = 1 / cosx

Therefore, sec 135° = 1 / (cos 135°)

Find the reference angle

135° is quite a complicated angle, but it is possible to simplify it by finding its reference angle.

Since 135° is in the second quadrant, its reference angle will be

180° - 135° = 45°

However, we need to consider the positive and negative.

In a coordinate plane, the clue is (A S T C), which corresponds to the positive values in each quadrant. In the QI, "All" are positive. In the QII, sine is positive. In the QIII, the tangent is positive. In QIV, cosine is positive.

Therefore, when the value of cosine is in QII, it is negative.

The reference angle = - (1 / cos 45°)

Determine the final value

Given that the reference angle = - (1 / cos 45°)

cos 45° = 1 / √2

Therefore:

sec 135° = - (1 / cos 45°) = - (1 / (1 / √2)) = $\boxed{-\sqrt{2} }$

Hope this helps!! :)

Please let me know if you have any questions

5 0

2 years ago