Please help I need it please please please

Mathematics

1 answer:

Marysya12 [62]2 years ago

8 0

Answer:

the first i think

Step-by-step explanation:

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GUYS PLEASE HELP ME I REALLY DON'T UNDERSTAND THIS TASK!!!!!!! IT'S VERY IMPORTANT FOR ME!!!!! DISTANCE BETWEEN TWO TOWNSHIPS, E

Dimas [21]

For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.

5 0

3 years ago

Select all names that apply to the Number <br> √4

never [62]

Answer:

$\sqrt{4} = 2$

Step by step explaination:

$\sqrt{4} \\ = \sqrt{ {2}^{2} } \\ = 2$

7 0

3 years ago

Read 2 more answers

Write an equation of the line passing through the point A(8, 2) that is perpendicular to the line y = 4x−7.

Kay [80]

Answer:

y = - 1/4 + 4

Step-by-step explanation:

y = 4x - 7

Slope = 4

Slope of the perpendicular line = -1/4

Point (8,2)

(b) y-intercept: 2 - (-1/4)(8)

= 2 + 2 = 4

4 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$