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saul85 [17]
2 years ago
8

Please help I need it please please please

Mathematics
1 answer:
Marysya12 [62]2 years ago
8 0

Answer:

the first i think

Step-by-step explanation:

You might be interested in
3 a western beach is reducing width by 10 feet every 5 years for the first 10 years the patter then became less constant dunes b
Anna71 [15]

A. Western Beach is reducing was width by 10 feet every 5 years for the first 10 years, then the pattern became less constant. Dunes Beach experienced a stable and fast increase in width, 25 feet every 5 years of 5 feet per year.

B. Somewhere between years 11 and 12 they had the same width.

C. You can place the values on a graph and connect the points, and look at the intersections to determine points in time where they were of the same width.

First, lets look at the data. Western Beach (or WB for short) decreases its width by 10 feet every 5 years from year 0 to year 10. Between year 11 and year 15 the pattern shifts and becomes less changing since there is barely any change between years 12 and 15. Dunes Beach (or DB) increases steadily by 25 feet every 5 years or 5 feet per year.

Assuming the changes in width happen over time and gradually, at some point between year 10 and 11, both beaches would have likely had the same width, somewhere between 70 and 75.

To determine the exact point in time where they meet we would need to draw a graph, with the width in feet on the X axis and the year on the Y axis. Then we place all the pairs in the graph by their coordinates, and connect the points that correspond to each beach. We then see where the lines intersect and use mathematics to determine the values of X and Y, giving us the time and width when the two beaches were equal.

please mark me brainliest it helps to become an genius

4 0
3 years ago
How do I do this?need help​
Lelu [443]
I have no clue at all
8 0
3 years ago
What number is four times as many as 25
Nana76 [90]

Answer:

100

Step-by-step explanation:

4 x 25 = 100

7 0
4 years ago
What three consecutive integers equal -87?
olchik [2.2K]

Answer:

What three consecutive integers have a sum of 87? Which means that the first number is 28, the second number is 28 + 1 and the third number is 28 + 2. Therefore, three consecutive integers that add up to 87 are 28, 29, and 30. We know our answer is correct because 28 + 29 + 30 equals 87 as displayed above.

Step-by-step explanation:

Consecutive integers are as simple as 1, 2, 3!  

Integers are consecutive if one follows another.  How do we "jump" from one integer to the next?  We add 1, right?  7, 8 and 9 are three consecutive integers.  Add one to 7 to get 8 and add one more to get 9.

Now lets think about this in algebraic terms.  Lets name these consecutive integers , x, y and z.  

The problem tells us that their sum is -87.  (Recall, "sum" is just a fancy word for the answer when we add.)

x+y+z = -87  

Here is the trick!  We need to rewrite this equation so that we have only one variable.  Easy!

y is one more that x, so y= x+1

And z is one more than y, so z= y+1.  But y is also equal to (x+1)!  So z=y+1=(x+1)+1=x+2

Now we have a problem that we can solve!  x+(x+1)+(x+2)=-87.  

Combining term.:  3x+3=-87  

Subtract 3 from both sides of the equation:  3x=84

Divide each side of the equation by 3:  x=28

We have solved for x, but we are not done!  We need to find y and z.  I know you can do this.  Remember y is one more than x and z is one more than y.

Check your work!  Make sure these three consecutive numbers do in fact add up to -87.

4 0
3 years ago
A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
4 years ago
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