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Igoryamba
2 years ago
10

If you are finding the range of a data set, are you finding a measure of center or a measure of variation?

Mathematics
1 answer:
zubka84 [21]2 years ago
6 0

Answer:

i think variation

Step-by-step explanation:

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2 years ago
Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv
uysha [10]

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(more than 4.25 minutes to solve a problem)

P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

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Answer:

its in the image below because im too lazy to write it down.

Step-by-step explanation:

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