Which is the equation of the line with slope 3 that contains point (-1, 5)?

1 answer:

5 0

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3[x-(-1)] \\\\\\ y-5=3(x+1)\implies y-5=3x+3\implies y=3x+8$

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