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2 years ago

Which is the equation of the line with slope 3 that contains point (-1, 5)?

1 answer:

5 0

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3[x-(-1)] \\\\\\ y-5=3(x+1)\implies y-5=3x+3\implies y=3x+8$

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Answer:

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2 years ago

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3 years ago

Read 2 more answers

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solmaris [256]

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3 years ago

Hello can someone answer please

tatyana61 [14]

Answer:

hello thereeeee

ans is 23.5

Step-by-step explanation:

so lets start

first of all remove decimal of divisor 1.1/25.85 multiplying by 10

11/258.5

now first multiply by 2

now we get 22 and subtract with 25 => 25-22 = 3

so left is

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so now by 3

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bringing another 5 down

we get 55

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23.5 is answer

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2 years ago