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3 years ago

Which is the equation of the line with slope 3 that contains point (-1, 5)?

1 answer:

5 0

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3[x-(-1)] \\\\\\ y-5=3(x+1)\implies y-5=3x+3\implies y=3x+8$

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Calculate the sum of the multiples of 4 from 0 to 1000

allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is $\sum\limits_{n=0}^n a+nd$ = (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 = (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

= (2*0 + (251-1)4)251/2

= (250*4)251/2

= 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is $\sum\limits_{n=0}^n a+nd$ = (2a+(n-1)d)n/2

3 0

3 years ago

Evaluate the expression for K=-16,m=-22,and n=-23.k+m+n

lys-0071 [83]

Answer:

-16-22-23= -61

Step-by-step explanation:

Hope it was helpful .

4 0

3 years ago

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v>=2i-4tj^

guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

$d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j$

B )

Acceleration a is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j$

Hence , this is the required solution .

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%

White raven [17]

Answer:

[Tex] \:/:/://///////////////////////////////////////::::::::::::::::::::::::::::::::7474838383+$83+

Answer = fracfracfracfrac tex tex????????????

8 0

3 years ago

The manager of a shopping mall distributed a customer-satisfaction survey by handing it to people as they came through one of th

Tresset [83]

Answer:

The correct option is D. No, because a random sample from all customers of the shopping mall was not selected

Step-by-step explanation:

In statistics, Bias can be described as a term which depicts error if a sample is not taken evenly or it depicts errors taken from an unjust sampling.

In statistics, sampling bias means the errors which occur if one part of the population is favoured more then the rest of the populations. In this kind of bias, the individuals for experimentation are not chosen randomly.

As the customer satisfaction survey was distributed in only one of the gates hence, it does not give a generalized result and the result is biased.

6 0

3 years ago

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