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Alborosie
3 years ago
12

If the altitude is 7 squared find the volume

Mathematics
1 answer:
aksik [14]3 years ago
6 0

Answer:

12*sqrt(7)

Step-by-step explanation:

The formula for volume is a^2*(h/3). Volume=36*sqrt(7)/3=12*sqrt(7)

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I'm bored but here is a trivia questions. These are like 4-5 grade level work I learned like 3 years ago.
Arisa [49]

Answer: A = 0.21

Step-by-step explanation:

4 0
3 years ago
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In a race Brian Collins has to cross 10 hurdles. Find the probability that he jumps a hurdle is 2/3. Find p(knocks down all hurd
Natalija [7]

Answer:  Option 'a' is correct.

Step-by-step explanation:

Since we have given that

Probability that he jumps a hurdle = \frac{2}{3}

Total number of hurdles = 10

Probability that he knocks down = 1-\frac{2}{3}=\frac{1}{3}

So, Probability (knocks down all hurdles ) is given by

(\dfrac{1}{3})^{10}\\\\=\dfrac{1}{59049}

Hence, Option 'a' is correct.

4 0
3 years ago
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The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T
Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. In this problem, \sigma = 0.25

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

M = z*\frac{\sigma}{\sqrt{n}}

0.1 = 1.96*\frac{0.25}{\sqrt{n}}

0.1\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.1}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}

n = 24.01

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

M = z*\frac{\sigma}{\sqrt{n}}

0.06 = 1.96*\frac{0.25}{\sqrt{n}}

0.06\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.06}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}

n = 66.7

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

M = z*\frac{\sigma}{\sqrt{n}}

0.05 = 1.96*\frac{0.25}{\sqrt{n}}

0.05\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.05}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}

n = 96.04

Rounding up, 97

8 0
3 years ago
5 times 2/8=
sergejj [24]

Answer:

STEP

1

:

           12

Simplify   ——

           1  

Equation at the end of step

1

:

    -15       k        5      

 (((————)+((8•—)•k))-————————-10k)+(12•k2))-5k)-12

    (k2)      2      (k3)(k2)

STEP

2

:

Equation at the end of step 2

    -15       k        5      

 (((————)+((8•—)•k))-————————-10k)+(22•3k2))-5k)-12

    (k2)      2      (k3)(k2)

STEP  

3

:

Equation at the end of step

3

:

    -15       k        5    

 (((————)+((8•—)•k))-——————-10k)+(22•3k2))-5k)-12

    (k2)      2      (k3)k2

STEP  

4

:

            5

Simplify   ——

           k3

Equation at the end of step

4

:

    -15       k       5  

 (((————)+((8•—)•k))-————-10k)+(22•3k2))-5k)-12

    (k2)      2      k3k2

STEP

5

:

           k

Simplify   —

           2

Equation at the end of step

5

:

    -15       k       5  

 (((————)+((8•—)•k))-————-10k)+(22•3k2))-5k)-12

    (k2)      2      k3k2

STEP  

6

:

           15

Simplify   ——

           k2

Equation at the end of step

6

:

    15        5  

 (((——)+4k2)-————-10k)+(22•3k2))-5k)-12

    k2       k3k2

5 0
3 years ago
If you could count $1 per second, how many years would it take to count a 1 billion
pogonyaev
I do believe it's 273,972 years.
6 0
4 years ago
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