3/5 x 30 days = 18 days were sunny.
Answer with Step-by-step explanation:
We are given that
![f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.](https://tex.z-dn.net/?f=f%28x%29%3D%5Cleft%5C%7B%5Cbegin%7Bmatrix%7D%5Cdfrac%7Bx%5E2-2x%7D%7Bx%5E2-4%7D%26%2Cif%5C%20%5C%20x%5Cneq%202%20%5C%5C%201%26%2Cif%5C%20%5C%20x%3D2%5Cend%7Bmatrix%7D%5Cright.)
We have to explain that why the function is discontinuous at x=2
We know that if function is continuous at x=a then LHL=RHL=f(a).
![f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7Bx%28x-2%29%7D%7B%28x%2B2%29%28x-2%29%7D%3D%5Cfrac%7Bx%7D%7Bx%2B2%7D)
LHL=Left hand limit when x <2
Substitute x=2-h
where h is small positive value >0
![\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}](https://tex.z-dn.net/?f=%5Clim_%7Bh%5Crightarrow%200%7Df%28x%29%3D%5Clim_%7Bh%5Crightarrow%200%7D%5Cfrac%7B2-h%7D%7B2-h%2B2%7D)
![\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}](https://tex.z-dn.net/?f=%5Clim_%7Bh%5Crightarrow%200%7D%5Cfrac%7B2-h%7D%7B4-h%7D%3D%5Cfrac%7B2%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B2%7D)
Right hand limit =RHL when x> 2
Substitute
x=2+h
![\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}](https://tex.z-dn.net/?f=%5Clim_%7Bh%5Crightarrow%200%7Df%28x%29%3D%5Clim_%7Bh%5Crightarrow%200%7D%5Cfrac%7B2%2Bh%7D%7B2%2Bh%2B2%7D%3D%5Clim_%7Bh%5Crightarrow%200%7D%5Cfrac%7B2%2Bh%7D%7B4%2Bh%7D)
![=\frac{2}{4}=\frac{1}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B2%7D)
LHL=RHL=![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
f(2)=1
![LHL=RHL\neq f(2)](https://tex.z-dn.net/?f=LHL%3DRHL%5Cneq%20f%282%29)
Hence, function is discontinuous at x=2
10 000
Anything greater than 5 rounds up
Hope this helps :)
3. 16 months
60x=947
x=15.78333… = 16 months
4. 46 months
400x=18,091
x=45.2275 = 46