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3 years ago

The average of Aaron's three test scores must be at least 93 to earn an A in the class. Aaron scored 89 on the first

Mathematics

1 answer:

victus00 [196]3 years ago

4 0

Answer:

Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.

Step-by-step explanation:

Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:

93 x 3 = 279

89 + 94 + S = 279

S = 279 - 89 - 94

S = 96

Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.

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ben went to the hardware store and bought 15 pieces of rope of equal length.The total length of the ropes was 326.7 meters.How l

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3 years ago

The volume v of a gas kept at constant temperature varies inversely with the pressure p. If the pressure is 24 pounds per square

daser333 [38]

Answer:

$V=12\ ft^{3}$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

In this problem

$P*V=k$

step 1

Find the value of K

For $P=24\ psi ,V=15\ ft^{3}$

substitute

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the equation is $P*V=360$

step 2

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3 years ago

According to a recent study of 7335 young people in the US, 30% had been arrested for a crime other than a traffic violation by

victus00 [196]

Answer:

a) Statistic.

b) The population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.

Step-by-step explanation:

a) The proportion of 30% is a statistic, as it is a value that summarizes data only from the sample taken in the study from USA Today. Other samples may yield different proportions.

b) We can use the statistic to estimate a confidence interval for the parameter of the population.

The standard error for the proportion is calculated as:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{N}}=\sqrt{\dfrac{0.3\cdot 0.7}{7335}}=\sqrt{2.83\cdot10^5}= 0.00535$

The margin of error is 0.01. We can use this value to determine the level of confidence that represents.

The formula for the margin of error is:

$E=z\cdot \sigma_p=0.01\\\\z\cdot 0.0535=0.01\\\\z=1.87$

This z-value, according to the the standard normal distribution, corresponds to a confidence interval of 94%.

The interval for this margin of error is:

$p-E\leq \pi \leq p+E\\\\0.30-0.01\leq \pi \leq 0.30+0.01\\\\0.29\leq \pi \leq 0.31$

Then, we can conclude that the population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.

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4 years ago