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lozanna [386]
3 years ago
13

I require help with this problem

Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0
X =13 because it’s a 45-45-90 triangle and the sides take the 13square root of 2 and take the 2 out and you get 13. Sorry for the weird explanation, hope you understood.
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Step-by-step explanation:

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Given m||n, find the value of x.<br><br> (2x+9)<br> (7X+24)
motikmotik

<em>Given, 9−7x=5−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x⇒x= </em><em>4</em><em>/</em><em>4</em><em> </em><em> =1</em>

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Step-by-step explanation:

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5 0
3 years ago
Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand
kvasek [131]

Answer:

(a)\frac{5}{7},\frac{1}{6} (b)\frac{1}{7},\frac{1}{6} (c)\frac{5}{7},\frac{2}{3},\frac{3}{5}

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag =7

(a)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing red marble  =\frac{\text{total red marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(b)

Probability of drawing red marble =\frac{\text{total red marble}}{\text{total marbles}}

                                                          =\frac{1}{7}

As marble is not returned to bag,

Probability of drawing white marble  =\frac{\text{total white marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(c)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing second blue marble  =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                         =\frac{4}{6}=\frac{2}{3}

As marble is not returned to the bag

Probability of drawing third blue marble   =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                    =\frac{3}{5}

8 0
3 years ago
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