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IRINA_888 [86]
3 years ago
5

Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartF

raction sine (uppercase C) Over c EndFraction In △BCD, d = 3, b = 5, and m∠D = 25°. What are the possible approximate measures of angle B? only 90° only 155° 20° and 110° 45° and 135°
Mathematics
2 answers:
jekas [21]3 years ago
4 0

Answer:

c

Step-by-step explanation:

just took the test!

Korvikt [17]3 years ago
3 0

Answer:

I think it's C

Step-by-step explanation:

I just took the test.

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Find the range of values:
Valentin [98]

Answer:

9-10cm

Step-by-step explanation:

You have to find out all the infermation

6 0
3 years ago
The product of nine and the total of r and eight
yuradex [85]

Answer:

9(r + 8) = 9r +72

Step-by-step explanation:

9(r + 8)

9r + 72

Hope this helps!

7 0
2 years ago
BC=CD what is the property
Andre45 [30]
  • Distributive Property AB + AB = 2AB
  • Reflexive Property m>B = m>B
  • Symmetric Property If AB + BC = AC then AC = AB + BC
  • Transitive Property If AB ≅ BC and BC ≅ CD then AB ≅ CD
5 0
2 years ago
In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3
Sliva [168]

Answer:

i) it is not possible for the student to receive an A in the class

ii) 119 points

iii) 84points

Step-by-step explanation:

Total exam scores = 350points

homework scores of 7, 8, 7, 5, and 8

Let the third exam score =y

Exam scores = 81, 80, x

i) To know if the student would get an A in class, we would find the third exam score

(Scores received by a student)/ (total scores) = least of the grade percentage to get an A

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.9

(196+x)/350 = 0.9

196+x = 350 × 0.9

196+x = 315

x = 315-196

x = 119

119 > 100

Since the maximum grade for each of the exam score is 100points, it is not possible for the student to receive an A in the class.

ii) Since the least of the grade percentage that would guarantee an A is 0.9, the minimum score on the third exam that will give an A = 119points

iii) (Scores received by a student)/ (total scores) = least of the grade percentage to get a B

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.8

(196+x)/350 = 0.8

196+x = 350 × 0.8 = 280

x = 280-196

x = 84

The minimum score on the third exam that will give a B = 84points

3 0
3 years ago
last summer, at camp okey-fun-okey, the ratio of the number of boy campers to girl campers was 8:7. If there were a total of 195
Evgen [1.6K]

The ration of boy campers to total campers is 8:15, and the ratio of girl campers to total campers is 7:15.  Using this information, we can answer this question by setting up proportions.

<u>For boys:</u>

\frac{8}{15} =\frac{x}{195}

<em>*Cross multiply*</em>

15x=1560

<em>*Divide both sides by 15*</em>

x=104

There are 169 boy campers.


<u>For girls:</u>

\frac{7}{15} =\frac{x}{195}

<em>*Cross multiply*</em>

15x=1365

91=x

There are 91 girl campers.


Hope this helps!!

7 0
3 years ago
Read 2 more answers
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