The product of 8 and a number, rised to the power of two-thirds
ok ... in this situation... we need to find the area of the rectangle first as it is equal to the area of square .
so .... area of rectangle = l×b= 16×4
= 64 ∴area of square = 64
area of square = s×s
∴to find one side of the square ... we need to find the root of 64 = 8
∴one side = 8
now : perimeter of square : 4 × sides = 4 × 8 = 32 ║
Answer:
Step-by-step explanation:
We expect the equation for y to be quadratic. Since the table is obviously symmetrical about x=3, we can start with the vertex form ...
y = a(x -3)² +b
Filling in the values from the first two table points, we get
For (x, y) = (0, 6):
6 = a(0 -3)² + b ⇒ 9a +b = 6
For (x, y) = (2, 22):
22 = a(2-3)² +b ⇒ a +b = 22
Subtracting the second equation from the first gives ...
(9a +b) -(a +b) = (6) -(22)
8a = -16 . . . . . . collect terms
a = -2 . . . . . . . . divide by 8
The second equation above tells us ...
b = 22 -a = 22 -(-2) = 24
So, our equation for y is ...
y = -2(x -3)² +24
__
The value of y for x=5 is ...
y = -2(5 -3)² +24 = 16
The height of the ball after 5 seconds is 16 feet.
<span>Simplifying
12 + -6(w + -3) = 3(-5 + -3w) + 21
Reorder the terms:
12 + -6(-3 + w) = 3(-5 + -3w) + 21
12 + (-3 * -6 + w * -6) = 3(-5 + -3w) + 21
12 + (18 + -6w) = 3(-5 + -3w) + 21
Combine like terms: 12 + 18 = 30
30 + -6w = 3(-5 + -3w) + 21
30 + -6w = (-5 * 3 + -3w * 3) + 21
30 + -6w = (-15 + -9w) + 21
Reorder the terms:
30 + -6w = -15 + 21 + -9w
Combine like terms: -15 + 21 = 6
30 + -6w = 6 + -9w
Solving
30 + -6w = 6 + -9w
Solving for variable 'w'.
Move all terms containing w to the left, all other terms to the right.
Add '9w' to each side of the equation.
30 + -6w + 9w = 6 + -9w + 9w
Combine like terms: -6w + 9w = 3w
30 + 3w = 6 + -9w + 9w
Combine like terms: -9w + 9w = 0
30 + 3w = 6 + 0
30 + 3w = 6
Add '-30' to each side of the equation.
30 + -30 + 3w = 6 + -30
Combine like terms: 30 + -30 = 0
0 + 3w = 6 + -30
3w = 6 + -30
Combine like terms: 6 + -30 = -24
3w = -24
Divide each side by '3'.
w = -8
Simplifying
w = -8</span>
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