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-Dominant- [34]
1 year ago
10

margaret drove to a business appointment at 70 mph. her average speed on the return trip was 60 mph. the return trip took 1 6 hr

longer because of heavy traffic. how far did she travel to the​ appointment?
Mathematics
1 answer:
Anon25 [30]1 year ago
4 0

The distance travelled to the appointment is 6720 miles

<h3>How to find the distance she travelled for the appointment?</h3>

Since margaret drove to a business appointment at 70 mph.

So, the distance on the trip,d = vt where

  • v = speed to business appointment = 70 mph and
  • t = time to business appointment

So, d = 70t

Since her average speed on the return trip was 60 mph. the return trip took 16 hr longer because of heavy traffic.

The distance on the return trip, D = v't' where

  • v = speed on return trip = 60 mph and
  • t = time on return trip = t + 16

So, D = 60(t + 16)

Since both distances are equal, we have that

d = D

70t = 60(t + 16)

70t = 60t + 960

70t - 60t = 960

10t = 960

t = 960/10

t = 96 h

Since the distance to the appointment d = 70t

Substituting t = 96 into the equation, we have

d = 70t

d = 70 × 96

d = 6720 miles

So, the distance to the appointment is 6720 miles

Learn more about distance here:

brainly.com/question/24295081

#SPJ1

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