Answer:
The probability of friend A winning with HH = 1/4.
Step-by-step explanation:
The probability of an event, A is P(A) given by the relationship;
P(A) = (The number of required outcome)/(The number of possible outcomes)
The parameters given are;
The condition of friend A winning = Coin toss sequence HH shows up
The condition of friend B winning = Coin toss sequence TH shows up
The number of possible outcomes = TT, TH, HH, HT = 4
(TH and HT are taken as different for the game to be fair)
The number of required outcome = HH = 1
Therefore;
The probability of friend A winning with HH = 1/4.
Answer:
=−1/2
Step-by-step explanation:
So to find x, you have to add both A and B which is 38. Since AuB (excluding the overlap) is 29, subtract 38 from 29 and you get 9 for x.
Answer:
$18
Step-by-step explanation:
9 multiplied by 2 equals 18.
Hope this helps :)
Answer:
2:6 in its simplest form would be 1:3
Hope this helps!
Mark me brainliest of I'm right :)
