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defon
3 years ago
6

Determine another point on the line given two points on the line. (-2, 9), (2, -1)

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

(4,-6)  

Step-by-step explanation:

1) First, let's find the slope of the line between the two points. Use the slope formula m = \frac{y_2-y_1}{x_2-x_1}, substitute the x and y values of (-2,9) and (2,-1) into it, then solve:

m = \frac{(-1)-(9)}{(2)-(-2)}\\m = \frac{-1-9}{2+2} \\m =\frac{-10}{4} \\m = -\frac{5}{2}

So, the slope of the line is -\frac{5}{2}.

2) Now, using that slope, let's find another point on the line. You can do this by drawing the two points on a graph (picture below). Now, remember that the slope is \frac{rise}{run}. So, starting from any of the two points (I chose (2,-1), as seen below) count 5 units down, then 2 units to the right. This gives an answer, (4,-6).

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3 years ago
Estimate the solution to the system of equations.
Leona [35]

Answer:

\sf C)  \  x = -1\dfrac{2}{5}  , \  y =  \ 1\dfrac{3}{5}

Given equations:

  • a) -3x + 3y = 9
  • b) 2x - 7y = -14

<u>Make x the subject in equation 1</u>:

  • -3x + 3y = 9
  • -3x = 9 - 3y
  • x = y - 3

<u>Substitute this into equation 2</u>:

2(y - 3) - 7y = -14

2y - 7y = -14 + 6

-5y = -8

  y = -8/-5

  y = 1.6

Then x = y - 3

           = 1.6 - 3

           = -1.4

Solution: (x, y) ⇒ (-1.4, 1.6)

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2 years ago
Find all maxima and minima of the function given below. Use a horizontal span of -6 to 6. (Round your answers to two decimal pla
AVprozaik [17]
Equation: 4 + 4x + x²

Maxima: No maximum value from said equation
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3 years ago
What is the sum of -19 and the product of 48 ?
IceJOKER [234]
It has to be -912 because i checked on a caculator
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3 years ago
A 200-liter tank initially full of water develops a leak at the bottom. Given that 20% of the water leaks out in the first 5 min
Leya [2.2K]

Answer:

127.53 liters left after 10 minutes

Step-by-step explanation:

Let

A \to Amount

t \to time

Given

A(0) = 200 --- initial

A(5) = 200 * (1 - 20\%) = 160 --- the amount left, after 5 minutes

Required

A(10) --- amount left after 5 minutes

To do this, we make use of:

A(t) = A(0) * e^{kt}

A(5)  = 160 implies that:

160 = 200 * e^{k*5}

Divide both sides by 200

0.80 = e^{k*5}

Take natural logarithm of both sides

\ln(0.80) = \ln(e^{k*5})

\ln(0.80) = \ln(e^{5k})

\ln(0.80) = 5k\ln(e)

So, we have:

-0.223 = 5k

Divide by 5

k = -0.045

So, the function is:

A(t) = A(0) * e^{kt}

A(t) = 200 * e^{-0.045t}

The amount after 10 minutes is:

A(10) = 200 * e^{-0.045*10}

A(10) = 200 * e^{-0.45}

A(10) = 127.53

3 0
3 years ago
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