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defon
3 years ago
6

Determine another point on the line given two points on the line. (-2, 9), (2, -1)

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

(4,-6)  

Step-by-step explanation:

1) First, let's find the slope of the line between the two points. Use the slope formula m = \frac{y_2-y_1}{x_2-x_1}, substitute the x and y values of (-2,9) and (2,-1) into it, then solve:

m = \frac{(-1)-(9)}{(2)-(-2)}\\m = \frac{-1-9}{2+2} \\m =\frac{-10}{4} \\m = -\frac{5}{2}

So, the slope of the line is -\frac{5}{2}.

2) Now, using that slope, let's find another point on the line. You can do this by drawing the two points on a graph (picture below). Now, remember that the slope is \frac{rise}{run}. So, starting from any of the two points (I chose (2,-1), as seen below) count 5 units down, then 2 units to the right. This gives an answer, (4,-6).

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6. Find the HCF of : (a) 21xy³ and 24x²y² (b) 18ab and 36abc <br>(c) 4p³q²r , -12pr² , 16p²q²r²r²​
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Step-by-step explanation:

<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>

Given monomials are 21 xy³ and 24x²y²

21 xy³ = 3×7×x×y×y×y

24x²y² = 3×8×x×x×y×y

HCF of 21xy³ and 24x²y²

=> 3×x×y×y

=> 3xy²

HCF of 21xy³ and 24x²y² = 3xy²

<h2>b)</h2>

Given monomials are 18 ab and 36abc

18 ab = 18×a×b

36abc = 2×18×a×b×c

HCF of 18 ab and 36abc

=> 18×a×b

=> 18ab

HCF of 18 ab and 36abc = 18ab

<h2>c)</h2>

Given monomials are 4p³q²r , -12pqr² and 16p²q²r²

4p³q²r = 4×p×p×p×q×q×r

-12pqr² = -3×4×p×q×r×r

16p²q²r² = 4×4×p×p×q×q×r×r

HCF of 4p³q²r , -12pqr² and 16p²q²r²

=> 4×p×q×r

=> 4pqr

HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr

<h2><u>Used Concept :-</u></h2>

→ The HCF of two or more numbers is the highest Common factor

→ The product of least common factors is the HCF of the numbers

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