Answer:
x = 5
Step-by-step explanation:
im too tired to explain just trust me
(5) + 2 = 7
2(5) + 3 = 13
13 * 7 = 91
Answer:
The probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Step-by-step explanation:
Let <em>X</em> = number of household owns a sports car.
The probability of <em>X</em> is, P (X) = p = 0.07.
Then the random variable <em>X</em> follows a Binomial distribution with <em>n</em> = 3 and <em>p</em> = 0.07.
The probability function of a binomial distribution is:
![P(X=x) = {n\choose x}p^{x}[1-p]^{n-x}\\](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%7Bn%5Cchoose%20x%7Dp%5E%7Bx%7D%5B1-p%5D%5E%7Bn-x%7D%5C%5C)
Compute the probability that of the 3 households randomly selected at least 1 owns a sports car:

Thus, the probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
QUESTION A
The given multiplication problem is

Factor each term to obtain;

Cancel out the common factors to obtain;

Simplify to get;

QUESTION B
The given multiplication problem is

This the same as

This simplifies to;

QUESTION C
The given problem is

This is the same as


This simplifies to

QUESTION D.
The given expression is

Factor the 54 to obtain;

Cancel the common factors to get;

This simplifies to;

QUESTION E
The given problem is

Convert the mixed numbers to improper fraction to obtain;


Cancel the common factors to get;


QUESTION F
The multiplication problem is

Convert the mixed numbers to improper fractions to obtain;

Cancel out the common factors to get;

Simplify;

QUESTION G
The given problem is

Convert to improper fractions;

Cancel out the common factors to get;


Convert back to mixed numbers

QUESTION H
The given expression is

Convert to improper fraction to get;

Cancel common factors to get;

Simplify

Convert back to mixed numbers;

Answer:
bus = 43
van 12
Step-by-step explanation:
This can be solved using simultaneous equations
Let v represent the number of students that a van carries
Let b represent the number of students that a bus carries
the following equations can be derived from the question
3v + 2b = 122 eqn 1
5v + 3b = 189 eqn 2
Multiply eqn 1 by 5 and eqn 2 by 3
15v + 10b = 610 eqn 3
15v + 9b = 567 eqn 4
Subtract equation 4 from 3
b = 43
Substitute for b in equation 1
3v + 2(43) = 122
solve for v
v = 12