Answer:
Yessirr
Step-by-step explanation:
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.
Number of sample, n = 41
Mean, u = 43.1 hours
Standard deviation, s = 5.91 hours
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
43.1 ± 1.645 × 5.91/√41
= 43.1 ± 1.645 × 0.923
= 43.1 ± 1.52
The lower end of the confidence interval is 43.1 - 1.52 =41.58
The upper end of the confidence interval is 43.1 + 1.52 =44.62
Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62
Answer:
no
negative 4 i think im dumb tho
Step-by-step explanation:
Answer:
1056.25 pi
Step-by-step explanation:
f the circumference of the circle is 65\pi, then the diameter is 65. If the diameter is 65, the radius is \frac{1}{2} * 65, and then you would do 32.5^2 * \pi, which would equal
Answer:
3 4/5
Step-by-step explanation:
just add the whole number then add the numerator then the denominator stay the same