Answer:
length = 18yd
Width = 10yd
Step-by-step explanation:
Complete question
<em>A rectangular parking lot has a length that is 8 yards greater than the width. The area of the parking lot is 180 square yards. Find the length and the width.</em>
Area of the parking lot - length * width
A = LW
Given
Area = 180sq. yd
If the parking lot has a length that is 8 yards greater than the width, then;
L = 8 + W
The area becomes;
A = (8+W)W
180 = 8W+W²
W²+8W - 180 = 0
W²+18W-10W - 180 = 0
W(W+18)-10(W+18) = 0
(W-10)(W+18) = 0
W-10 = 0
W = 10yd
Since L = 8 + W
L = 8 + 10
L = 18yd
Hence the length and the width area 18yd and 10yd respectively
Answer:
Step-by-step explanation:
Answer:
x = 20
Step-by-step explanation:
Assuming it's a square, all sides are congruent. This would mean that x is in fact 20. This also shows us that since the filled in portion of the square has a length of 4, the unfilled portion has a length of 16.
Answer:
put it on -1
Step-by-step explanation:
you turn the mixed number into an improper fraction and then you turn -11/6 to have a denominator of 3 so then it comes out to -1 1/2 over 3 then you multiply the 3 times 2 and the 1 1/2 times 2 and you get -3/3 and equals out to -1