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anastassius [24]
3 years ago
10

Can anyone help me with this problem

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

9514 1404 393

Answer:

  8. A = {Delaware, New Jersey, Pennsylvania}

  9. |B| = 3

Step-by-step explanation:

8. Dates prior to 1 Jan 1788 are those in 1787. The three states admitted in 1787 are listed as Delaware, Pennsylvania, New Jersey. It is usually convenient to list elements of a set in lexicographical order:

  A = {Delaware, New Jersey, Pennsylvania}

__

9. The months June and July appear 3 separate times on the list, so there would be 3 elements in the set B.

  |B| = 3

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Will give first person brainliest!
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Answer:

Step-by-step explanation:

D=106

E=54

F=20

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I hope this helps have a good day!

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Prove 2^n > n for all n equal to or greater than 1. I mostly need help with how to solve the problem when it is greater than
noname [10]
If n is an integer, you can use induction. First show the inequality holds for n=1. You have 2^1=2>1, which is true.

Now assume this holds in general for n=k, i.e. that 2^k>k. We want to prove the statement then must hold for n=k+1.

Because 2^k>k, you have

2^{k+1}=2\times2^k>2k

and this must be greater than k+1 for the statement to be true, so we require

2k>k+1

for k>1. Well this is obviously true, because solving the inequality gives 3k>1\implies k>\dfrac13. So you're done.

If you n is any real number, you can use derivatives to show that 2^n increases monotonically and faster than n.
7 0
3 years ago
Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
3 years ago
I need help with math
Nata [24]

Answer:

Question 13. I believe is C.

Step-by-step explanation:

take your area of the face you are given aka your 7 5/6 and multiply it by six since there are six faces.

You can convert the mixed number to an improper fraction

     7 \frac{5}{6}  = denominator times the whole number ( 6x7)= then add the numerator    (42+5)=\frac{47}{6}

Then multiply by six to get your answer

I'm not completely sure about question number fourteen so I am not answering it.

8 0
3 years ago
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