Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
Answer:
(0,-4) (5,0)
Step-by-step explanation:
4x-5y=20
First, we must put the equation into slope intercept form: y= mx+b
5y=4x-20=y=4/5x-4
The y intercept, by definition, is b. In this scenario, b is -4.
One ordered pair that works is (0,-4).
Also, we can find the ordered pair for the x intercept. By definition, the x intercept is the value of x when y equals zero. hence, we substitute 0 for y and then we can find an ordered pair that works and solve for x!:
- 0=4/5(x)-4= 4=4/5x
- 4x=20
- x=5
Therefore, (5,0) works as well!
A = 81 square in.
s = sqrt(A)
s = sqrt(81)
s = 9 in.
You're given two angles and the side not between them are congruent, so the AAS theorem applies. (2nd selection)
4x + 10 = 2x + 20
4x - 2x = 20 - 10
2x = 10
x = 5
