You need a length and width for it
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be = 
= 67.5feet
Therefore, the actual distance is 67.5feet
The correct answer is B) 9 m.
The measure of the sector of circle R is 32π/9 m. The measure of the central angle is 80°. This means that the sector is 80/360 = 2/9 of the circle. The area of a circle is given by A=πr², so the area of the sector is A=2/9πr². To verify this, 2/9π(4²) = 2/9π(16) = 32π/9.
Using this same formula for circle S, we will work backward to find the radius:
18π = 2/9πr²
Multiply both sides by 9:
18*9π = 2πr²
162π = 2πr²
Divide both sides by 2π:
162π/2π = 2πr²/2π
81 = r²
Take the square root of both sides:
√81 = √r²
9 = r
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