Answer:
x+1 , x<-1
x²-bx-4 , -1≤x≤4
1/2 x +a
substitute x=-1 , continuous everywhere
x+1=x²-bx-4 when x=-1
-1+1=-1²-b-4
<h2>1+b-4=0 ⇒ +b-3 ⇒ b=3</h2>
then for :
x²-bx-4=1/2 x +a for x=4
4²-4b-4=1/2x+a
16-4(3)-4=4/2+a
16-12-4-2=a
<h2>a=-2</h2>
the equations will be :
x+1
x²-3x-4
1/2x-2
I hope this help
Answer:
p = 22/5
Step-by-step explanation:
50p+5=225
Subtract 5 from each side
50p+5-5=225-5
50p = 220
Divide by 50
50p/50 = 220/50
p = 22/5
The location of the image of points <em>J </em>and <em>K </em>following a reflection across the x-axis are;
- J'(-3, -4), and K'(3, -4)
<h3>Which method can be used to find the image of a point following a reflection?</h3>
Coordinates of point are;
J(-3, 4), K(3, 4)
The given transformation is; A reflection across the x-axis
The representation of a reflection across the x-axis is presented as follows;
The image of <em>J </em>and <em>K </em>following a transformation across the x-axis are therefore;
Learn more about reflection transformation on the coordinate plane here:
brainly.com/question/8242111
#SPJ1
Answer:
N0 solution.
Step-by-step explanation:
x=-2y+1....(1)
x+2y=9....(2)
put equation (2) to equation (1)
-2y+1 + 2y=9
combine
-2y + 2y=9-1
0=8
No solution.
Answer:
ok, so whats the question??
Step-by-step explanation:
