2 years ago

I need to find the steady-state vector.

Mathematics

1 answer:

natta225 [31]2 years ago

5 0

Pls trust me a give me the crown it’s 0.5

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In ΔPQR, p = 75 inches, q = 73 inches and r=35 inches. Find the measure of ∠P to the nearest 10th of a degree.

soldi70 [24.7K]

Answer:

79.5

Step-by-step explanation:

a^2 =b^2+ c^2-2bc cos A

cos p = 73^2+35^2-75^2/2(73)(35)

cos p= 9229/5110

cosp=79.5

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2 years ago

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Are you to combine the answer or are they 2 separate equations you need to solve for y?

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Two college roommates have each committed to donating to charity each week for the next year. The roommates’ weekly incomes are

schepotkina [342]

Answer:

C. 5 weeks.

Step-by-step explanation:

In this question we have a random variable that is equal to the sum of two normal-distributed random variables.

If we have two random variables X and Y, both normally distributed, the sum will have this properties:

$S=X+Y\\\\\ \mu_S=\mu_X+\mu_Y=30+60=90\\\\\sigma_S=\sqrt{\sigma_X^2+\sigma_Y^2}=\sqrt{10^2+20^2}=\sqrt{100+400}=\sqrt{500}=22.36$

To calculate the expected weeks that the donation exceeds $120, first we can calculate the probability of S>120:

$z=\frac{S-\mu_S}{\sigma_S} =\frac{120-90}{22.36}=\frac{30}{22.36}=1.34\\\\P(S>120)=P(z>1.34)=0.09012$

The expected weeks can be calculated as the product of the number of weeks in the year (52) and this probability:

$E=\#weeks*P(S>120)=52*0.09012=4.68$

The nearest answer is C. 5 weeks.

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2 years ago