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Darya [45]
3 years ago
14

Please show all work, Hurry. Thank you

Mathematics
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

X equal to 2 your answer is ready

Ostrovityanka [42]3 years ago
6 0

Answer:

x equals 2 so two is the right anwer

You might be interested in
3 to the 2nd power plus 2 to the 3rd power
Amanda [17]

Answer:

<h2>17</h2>

Step-by-step explanation:

3^2=3\cdot3=9\\\\2^3=2\cdot2\cdot2=8\\\\3^2+2^3=9+8=17

8 0
2 years ago
Read 2 more answers
Evaluate: .25 (1.2 x 3 - 1.25) + 3.45
iragen [17]

The order to us solve is:

  1. Parentheses
  2. Multiplication
  3. Sum and subtraction

Let's go:

25(1.2\times 3 - 1.25) + 3.45\\25(3.6-1.25)+3.45\\25\times 2.35 + 3.45\\58.75+3.45\\62.2

Therefore, the result is 62.2.

7 0
3 years ago
Read 2 more answers
First right answer gets brilliant. Can someone please help? It is due today!
nikitadnepr [17]

Answer:

Step-by-step explanation:

A, x=31

E, b=11

N, m=61

Y, b=15

I, a=80

G, k=-78

U, x=-13

R, u=88

O, y=13

A, w=104

H, d=-7

V, n=1/36

Sorry, don't want to give away all the answers!

Hope this helps!!!

7 0
3 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
Let f(x) = x2 - 81. Find f-1(x).
dusya [7]
This is equivalent to finding a function g in which g(x^2-81)=x.

We simply reverse the actions of the initial function by adding 81 back and taking the square root.  Therefore, f^{-1}(x)=\sqrt{x+81}.
7 0
3 years ago
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