What is the decomposition of 43.586 to the nearest tenth

1 answer:

6 0

43.586- anything 5 and more rounds up, so the 6 rounds the 8 up to 9, the 9 rounds the 5 up to a 6, so your answer wound be 43.6 because 43.5(tenths)8(hundredths)6(thousandths), i hope this helps

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The cost of 2 plates of spaghetti & 1 plate of salad is $27.50. The cost for 4 plates of spaghetti & 3 salads is $59.50.

k0ka [10]

2a+1b=27.50

4a+2b=59.50

Multiply first equation by -4 and the second by 2 so you can drop off the a values then add the equations together. Then solve for b. You should get b=6.

Then plug b into one of the original equations and solve for a and you should get 10.75

So a plate of spaghetti is $10.75 and a salad is $6.

Please mark brainliest!

8 0

3 years ago

The perimeter of a square is equal to four times the length of a side. Write the direct v variation equation that represents the

sveticcg [70]

Answer: $y=4x$

Step-by-step explanation:

A direct variation equation has the form:

$y=kx$

Where k is a constant.

By definition, we know that the perimeter of the square is the sum of the lengths of its sides or, as all the sides are equal, you can multiply the lenght of any side by 4.

Then, knowing that y is the dependent value and x the independent value and the constant k=4, you can write the following direct variation equation that represents the situation.

$y=4x$

4 0

3 years ago

Identify the radius and center. x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$