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2 years ago

Can someone help me with this

Mathematics

1 answer:

Kitty [74]2 years ago

4 0

You can't see the picture, please reach out once i can see it

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HELLLLLLLLLLLLLLP PLLLLLLLSSS, I NEED HELP WITH THIS ANSWER

vlabodo [156]

It would be -4, and 9.2 because they sign is saying that x is less than or equal too 11.

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3 years ago

Read 2 more answers

What is 0.5 repeating as a fraction in simplest form

Solnce55 [7]

Answer:

5/9

Step-by-step explanation:

Start be letting x = 0.555...

Our original equation is:

x = 0.555...

There is only one digit repeating, the 5, so we multiply both sides of that equation by 10 and write it above the original equation.

10x = 5.555...

x = 0.555...

Now we subtract the second equation from the first equation as written above.

9x = 5

Divide both sides by 9.

x = 5/9

0.555... = 5/9

6 0

2 years ago

Name three radii of Circle S.

Talja [164]

Answer:

circle S radii SU, ST, SR

Circle U radii UT, US, UR

Step-by-step explanation:

Radii start in the middle of the circle to the end of the circle.

5 0

3 years ago

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What if its "greater than 9"

goblinko [34]

Answer:

its gotaa be a number thats atleast 10

Step-by-step explanation:

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2 years ago

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The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

2 years ago