The emf of a cell is mathematically given as
= 0.0532 v
<h3>What is the emf of a cell?</h3>
Generally, the equation for emf is mathematically given as

where,
Pb is lead
H is hydrogen
/ Pb has a standard reduction potential of -0.126 volts, while
/
has a standard reduction potential of 0.0 volts.

![[Pb^2^+] x [H^+]^2](https://tex.z-dn.net/?f=%5BPb%5E2%5E%2B%5D%20x%20%5BH%5E%2B%5D%5E2)
= 0.126 - 0.059/2 log 1 / [0.57] x [0.09]^2
= 0.0532 v
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Answer:
the left side of the line
Step-by-step explanation:
Answer:
The answer is "0.081"
Step-by-step explanation:
Dimes
Calculating total coins
P(for a dime) 
Calculating remaining coins
Nickels 
P(for nickel draw in second)
P(for a dime after that a nickel, without replacement)
You have to complete the square. When you do this you get an equation that looks like this: (x-3)^2 + (y+4)^2 = 4. So your center is (3, -4) and your radius is 2. That looks like B to me!!!