Answer:
first triangle (to left) b=8, second one c=17
Step-by-step explanation:
for the first triangle (one to the left) the hypotenuse is 9, so let's use the pythagorean formula.
A^2 + B^2 = C^2
^ ^ ^
^ ^ Hypotenuse
^ second side
first side
Substitute:
5^2 + b^2 = 9^2
SImplify:
25+b^2 = 81
Reduce:
b^2 = 64
Simplify:
b=8
In the second triangle, we are given 2 sides.
Let's do the same thing we did in the first one.
Givens:
A = 8
B = 15
Find:
C
Substitute:
8^2 + 15^2 = c^2
Simplify
64 + 225 = c^2
Reduce:
289 = c^2
Let's now square root both sides
square root of 289 is 17
so we are left with this:
c=17
Phew, you did it!
Hope this helped :))
Answer:
what is the question? if you want to simplify this then you simply use the order of operations. 2*5 is 10. 10+4*3-3*8
10+12-3*8
10+12-24
-2
The first number would be represented by x, the second as
x+2 and the third as
x+4. Together they equal 117, so x+x+2+x+4= 117. You can sinplify that to equal 3x+6=117. You then solve for x (subtract the 6 from both sides to get 3x=111, and then divide both sides by 3 and you get x=37). The three numbers would be 37,39, and 41. The smallest is 37.
6.724
6 is in the <em>ones</em> place
7 is in the <em>te</em><em>nths</em> place
2 is in the <em>hundredths</em> place
<em />4 is in the <em>thousandths</em> place
We want to round to the nearest hundredth, which means we'd either round down to 6.72 or round up to 6.73. This depends on the next digit.
If the next digit is greater than 5, we round up. If it's less than 5, we round down.
Since 4 is less than 5, we round down to 6.72.
