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3 years ago

Which function represents g(x), a reflection of f(x) = 4

Mathematics

1 answer:

mel-nik [20]3 years ago

7 0

Answer: Correct answer is C -I just took the test

we have the function f(x) = 4(1/2)x, and we want to reflex it over the x-axis.

you can see in the graph that the reflex over this axis changes the sign of f(x) in all the points (where f(0) = 4, g(0) = -4, f(1) = 2, g(1) = -2, and so on), then the reflex, g(x) is equal to -f(x)

now we have:

g(x) = -f(x) = - 4(1/2)x

then the right answer is the third option:

g(x) = -4(1/2)x

Step-by-step explanation:

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Answer:

one negative real root in [-5, -4]; two complex roots
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Step-by-step explanation:

A graphing calculator is a wonderful tool for this. It shows the one real root to be near -4.062, so between -5 and -4.

The value of the cubic at x = -5 is -315; at -4 it is +15, so the root is definitely between those values.

The one real root is isolated to being between (-5, -315) and (-4, 15). The complex roots are not isolated.

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