Answer:

Step-by-step explanation:

First rule I'm going to use is the quotient rule:


Secondly, I'm going to rewrite the radical.


Third, I'm going to use the product rule on the first term:


Fourth, I'm going to use power rule for both of the last two terms:


Answer:

Step-by-step explanation:
Since there are 20 students, this will be the denominator.
Now, to find how many students have a dog and a cat, you need to subtract all the numbers with 20. The leftover number will be the amount of students.
7+8+8=23
23-20=3
So, there are 3 students who have a dog and a cat.
So, the fraction will be 
Answer:
The function (gof)(x) is;

Explanation:
Given the functions;

Solving for the function;

so, we have;

Therefore, the function (gof)(x) is;

Answer:
285 words
Step-by-step explanation: