Ask question

Ask question

All categories

1 year ago

14

a magnifying glass makes objects appear 2.54 times largers than their actual size. How large does a 6-millimeter seed appear in

the magnifying glass

2 answers:

Mnenie [13.5K]1 year ago

7 0

Answer:

15.24 millimeters

Step-by-step explanation:

6 * 2.54 = 15.24 mm.

miss Akunina [59]1 year ago

5 0

Answer: should be 15.24

Step-by-step explanation: quick maths

You might be interested in

Use the properties of logarithms to expand the expression as a sum or difference, and/or constant multiple of logarithms. (Assum

Alecsey [184]

Answer:

$\log_5(9)+\frac{1}{2}\log_5(x)-3\log_5(y)$

Step-by-step explanation:

$\log_5(\frac{9\sqrt{x}}{y^3})$

First rule I'm going to use is the quotient rule:

$\log_b(\frac{m}{n})=\log_b(m)-\log_b(n)$

$\log_5(9\sqrt{x})-\log_5(y^3)$

Secondly, I'm going to rewrite the radical.

$\sqrt{x}=x^\frac{1}{2}$

$\log_5(9x^\frac{1}{2})-\log_5(y^3)$

Third, I'm going to use the product rule on the first term:

$\log_b(mn)=\log_b(m)+\log_b(n)$

$\log_5(9)+\log_5(x^\frac{1}{2})-\log_5(y^3)$

Fourth, I'm going to use power rule for both of the last two terms:

$\log_b(m^r)=r\log_b(m)$

$\log_5(9)+\frac{1}{2}\log_5(x)-3\log_5(y)$

6 0

2 years ago

Is this sequence arithmetic, geometric, or neither?<br> 45,50,65,70,85

Usimov [2.4K]

I think it is arithmetic

3 0

3 years ago

In a class 20 of students, 7 have a cat and

blsea [12.9K]

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Since there are 20 students, this will be the denominator.

Now, to find how many students have a dog and a cat, you need to subtract all the numbers with 20. The leftover number will be the amount of students.

7+8+8=23

23-20=3

So, there are 3 students who have a dog and a cat.

So, the fraction will be $\frac{3}{20}$

8 0

2 years ago

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Butoxors [25]

Answer:

The function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

Explanation:

Given the functions;

$\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}$

Solving for the function;

$(g\circ f)(x)=g(f(x))$

so, we have;

$\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}$

Therefore, the function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

5 0

7 months ago

Nick can type 30 words a minute.<br> How many words can be typed in 9.5 minutes?

Elza [17]

Answer:

285 words

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers