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1 year ago

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a magnifying glass makes objects appear 2.54 times largers than their actual size. How large does a 6-millimeter seed appear in

the magnifying glass

2 answers:

Mnenie [13.5K]1 year ago

7 0

Answer:

15.24 millimeters

Step-by-step explanation:

6 * 2.54 = 15.24 mm.

miss Akunina [59]1 year ago

5 0

Answer: should be 15.24

Step-by-step explanation: quick maths

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The Quinn family drove 228 miles in 4 hours at a constant rate. Which equation can be used to determine how far they traveled ea

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What can be used on this is the distance over time formula, so what you,do is divide 228 by 4 to get the distance traveled in one hour. And 288/4=57. So they traveled 57 mi in one hour. Hope this helped.

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Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

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2 years ago

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Step-by-step explanation:

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3 years ago

What can be constructed from polygons alone?

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Cone (not including the vertex)

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2 years ago

A rectangular lawn is 2 m longer than it is wide.

PtichkaEL [24]

Let's breadth be x

Length be x+2

ATQ

$\\ \sf\longmapsto x(x+2)=21$

$\\ \sf\longmapsto x^2+2x=21$

Use completing the square method

$\\ \sf\longmapsto 4(x^2+2x)=4(21)$

$\\ \sf\longmapsto 4x^2+8x=84$

$\\ \sf\longmapsto (2x)^2+2(2x)(2)=84$

$\\ \sf\longmapsto (2x)^2+2(2x)(2)+2^2=2^2+84$

$\\ \sf\longmapsto (2x+2)^2=88$

$\\ \sf\longmapsto 2x+2=\pm\sqrt{88}$

As it's dimensions we will take positive

$\\ \sf\longmapsto 2x+2\approx 9.7$

$\\ \sf\longmapsto 2x=9.7-2=7.7$

$\\ \sf\longmapsto x=3.8$

x+2=3.8+2=5.8

Now

$\\ \sf\longmapsto Perimeter=2(L+B)$

$\\ \sf\longmapsto perimeter=2(3.8+5.8)$

$\\ \sf\longmapsto perimeter=2(9.6)$

$\\ \sf\longmapsto Perimeter=19.2m$

Length of 1 strip=13m

Total strips

$\\ \sf\longmapsto \dfrac{19.2}{13}$

$\\ \sf\longmapsto 1.47strips$

She needs 2 strips

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2 years ago

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