3(2a-5) = 12-7a
6a-15=12-7a
6a+7a=12+15
13a= 27
27=3c-3(6-2c)
27=3c-18+6c
27+18=3c+6c
45=9c
C=45/9
C=5
6c-8-2c=-16
6c-2c=-16+8
4c=-8
C=-8/4
C=-2
cylinder:
V = πr²h
V = 3.14(2)² * 3
V = 3.14(4) * 3
V = 3.14(12)
V = 37.7m³
rectangular prism:
V = lwh
V = (2.4)(9)(5)
V = 108m³
the entirety of the sculpture:
V = volume of cylinder + volume of rectangular prism
V = 37.7 + 108
<u>V = 145.7m³</u>
Make 2 eqn, let a be apples and o be oranges:
1. 5a + 4o = 10
2. 5a + 5o = 11
set up an elimination:
1. minus 2.
5a + 4o = 10
- 5a + 5o = 11
____________
o = 1
sub “o” into one of the eqn
5a + 5(1) = 11
5a = 11-5
5a = 6
a = 6/5
a = 1.2
therefore, an orange costs $1.00 and an apple costs $1.20
I believe it is 2.44560420327
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
