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alekssr [168]
3 years ago
11

△ XYZ∼ △ DEF, YZ is 10 meters, ​ XZ ​ is 15 meters, and EF is 8 meters. What is ​ DF?

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0
Im not for sure on this but i would say DF is 13
s2008m [1.1K]3 years ago
4 0

△ XYZ∼ △ DEF, YZ is 10 meters, ​ XZ ​ is 15 meters, and EF is 8 meters. What is ​ DF?

Solution:

As, △ XYZ∼ △ DEF , so the ratio of sides of triangle is equal.

So, we have, \frac{XY}{DE} =\frac{YZ}{EF} =\frac{XZ}{DF}

Using, \frac{YZ}{EF} =\frac{XZ}{DF}

So, we get,\frac{10}{8} =\frac{15}{DF}

Now, to solve for DF, we must simplify

Simplifying,\frac{10}{8} =\frac{5*2}{4*2}=\frac{15}{DF)

\frac{5}{4} =\frac{15}{DF}

To simplify, Let us multiply by 4*DF on both sides

\frac{5*4DF}{4} =\frac{15*4DF}{DF}

\frac{5DF}{1} =\frac{15*4}{1}

So, 5 DF=15*4=60

To solve for DF, let us divide by 5 on both sides

\frac{5}{5} DF=\frac{60}{5}

\frac{1}{1} DF=\frac{12}{1}

So, DF=12meters

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Alex787 [66]

Answer:  ∠ J = 62° , ∠ K = 59° , ∠ L = 59°

<u>Step-by-step explanation:</u>

It is given that it is an Isosceles Triangle, where L J ≅ K J

It follows that ∠ K ≅ ∠ L

         ⇒ 5x + 24 = 4x + 31

         ⇒   x + 24 =         31

         ⇒   x         =           7

Input the x-value into either equation to solve for  ∠ K &  ∠ L:

∠ K = 5x + 24

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∠ K ≅ ∠ L  ⇒   ∠ L = 59

Next, find the value of  ∠ J:

∠ J +  ∠ K +  ∠ L = 180    Triangle Sum Theorem

∠ J  +   59  +  59 = 180

∠ J          + 118     = 180

∠ J                       = 62

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