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3 years ago

I NEED HELP PLZZZ

Mathematics

2 answers:

quester [9]3 years ago

6 0

24x is gonna be your answer

marishachu [46]3 years ago

4 0

Answer:

Actual distance = 24 km

Step-by-step explanation:

16 cm

2cm = 3 km

We could use a ratio to do this

16/2 = x/3

8=x/3

Multiply both sides by 3

24=x

Hope this helps :)

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Find all polar coordinates of point P where P = ordered pair 1 comma pi divided by 3.

baherus [9]

Answer:

(1, π/3 +2kπ), (-1, 4π/3 +2kπ) . . . where k is any integer

Step-by-step explanation:

Adding any multiple of 2π to the angle results in the same point in polar coordinates.

Adding 180° (π radians) to the point effectively negates the magnitude. As above, adding any multiple of 2π to this representation is also the same point in polar coordinates.

There are an infinite number of ways the coordinates can be written.

6 0

3 years ago

Read 2 more answers

10 points and brainliest. solve by elimination

evablogger [386]

Answer:

(3,-7) I think.

Step-by-step explanation:

3 0

3 years ago

Please please help me no links

Slav-nsk [51]

pretty sure it’s 108 because each angle of a pentagon is 108

4 0

3 years ago

Please help with geometry. 20 points, and another question worth 98 on my profile!

vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) $PR^{2} =PS*PT$

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In this problem we have that

$PR^{2} =PS*PT$

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u> states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle