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Yuliya22 [10]
2 years ago
13

Solve the system of equations: y= x^2 + 2x - 3 and y=3x+ 3.

Mathematics
1 answer:
Semenov [28]2 years ago
3 0

Answer:

(-2, -3)

(3, 12)

Step-by-step explanation:

To solve this, we're gonna get rid of the y's with substitution

x² + 2x - 3 = 3x + 3

Let's make this equation equal to zero

Subtract 3 from both sides

x² + 2x - 3 = 3x + 3

            - 3         - 3

x² + 2x - 6 = 3x

Subtract 3x from both sides

x² + 2x - 6 = 3x

    - 3x        - 3x

x² - x - 6 = 0

Factor the equation

(x - 3)(x + 2) = 0

This means x can be -2 or 3

Let's solve it with -2 first, plug the new x in y = 3x + 3

y = 3(-2) + 3

y = -6 + 3 = -3

Do the same for x = 3

y = 3(3) + 3

y = 9 + 3 = 12

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Answer:

(x, y) = (-2, -3)

WORK:

2x + 4y = -16  =

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(^ the two’s cancel out) =

6y = -18  =

(^ you need to divide 6 on both sides to get just y) =

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(^ the six’s cancel out) =

y = -3  =

(^ now you have to plug this in to get x) =

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2 years ago
A park has a large circle painted in the middle of the playground area.thecircle is divided into 4 equal sections And each secti
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Answer:

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Step-by-step explanation:

we know that

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