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Yuliya22 [10]
2 years ago
13

Solve the system of equations: y= x^2 + 2x - 3 and y=3x+ 3.

Mathematics
1 answer:
Semenov [28]2 years ago
3 0

Answer:

(-2, -3)

(3, 12)

Step-by-step explanation:

To solve this, we're gonna get rid of the y's with substitution

x² + 2x - 3 = 3x + 3

Let's make this equation equal to zero

Subtract 3 from both sides

x² + 2x - 3 = 3x + 3

            - 3         - 3

x² + 2x - 6 = 3x

Subtract 3x from both sides

x² + 2x - 6 = 3x

    - 3x        - 3x

x² - x - 6 = 0

Factor the equation

(x - 3)(x + 2) = 0

This means x can be -2 or 3

Let's solve it with -2 first, plug the new x in y = 3x + 3

y = 3(-2) + 3

y = -6 + 3 = -3

Do the same for x = 3

y = 3(3) + 3

y = 9 + 3 = 12

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C= -2/3 and so y= -1/3x-2/3

4) DO THE SAME STEP AS NUMBER 3 and enjoy!
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egoroff_w [7]
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Answer:

3: 0.625

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Step-by-step explanation:

8 0
3 years ago
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John and Ariana bought school supplies, John spent $10.65 on 4 notebooks and 5 pens. Ariana spent $7.50 on 3 notebooks and 3 pen
timurjin [86]

Cost of 1 notebook is $ 1.85 and cost of 1 pen is $ 0.65

<h3><u>Solution:</u></h3>

Let "a" be the cost of 1 notebook

Let "b" be the cost of 1 pen

Given that John spent $10.65 on 4 notebooks and 5 pens

cost of 1 notebook x 4 + cost of 1 pen x 5 = 10.65

4a + 5b = 10.65 ------ eqn 1

Given that Ariana spent $7.50 on 3 notebooks and 3 pens

3a + 3b = 7.50 ----- eqn 2

Let us solve eqn 1 and eqn 2 to get the values of "a" and "b"

Multiply eqn 1 with 3

12a + 15b = 31.95  ---- eqn 3

Multiply eqn 2 with 4

12a + 12b = 30 ------ eqn 4

Subtract eqn 4 from eqn 3

12a + 15b = 31.95

12a + 12b = 30

(-) ---------------------

3b = 1.95

b = 0.65

Substitute b = 0.65 in eqn 1

4a + 5(0.65) = 10.65

4a = 7.4

a = 1.85

Thus cost of 1 notebook is $ 1.85 and cost of 1 pen is $ 0.65

8 0
3 years ago
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Answer:

32 Meters

Step-by-step explanation:

A square has 4 equal sides so all you have to do is divide 128 by 4

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