The illustration of the given mathematical elements is as in the attached images.
<h3>Illustration of mathematical elements</h3>
For line segments;
- The beginning and end of the line are specified by the assigned alphabets.
However, for rays;
- The ray is illustrated to originate from a point and span on from there till infinity.
For angles;
- The alphabet in the middle of the set of 3 alphabets used to identify the angle represents the center point of where the angle is located.
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Okay we'll start easy
46*93
We will take 6*3 which is 18.
40*3 which is 120
6*90 which is 540
40*90 which is 3600
Now add up those
18+120+540+3600 which is 4278
So the missing numbers.
3._00 is going to be 3600
5_0 is going to be 540
_20 is going to be 120
1_ is going to be 18
4._78 is going to be 4.278
Hope this helped. ^~^
1a. 10. 24
1b. 125/243
2a. 0. 0048
2b. 32/3125
3a. 0. 64
3b. 0. 0031
4a. 2/5
4b. 48. 735
5a. 2. 36
5b. 1. 39
<h3>
How to determine the values</h3>
1a. Given the values
(2/5)^2/(1/2)^6
Multiply both the numerator and denominator by the powers
⇒ 
To find the common ration, multiply thus;
⇒
<em> × </em>
⇒ 
= 10. 24
1b. (5/7)^2 × (5/7)^1
=
× 
= 
= 125/243
2a. 0. 6^1 × 0. 2^3
= 0. 6 × 0. 008
= 0. 0048
2b. (2/5)^3 × (2/5)^2
=
× 
<em>= </em>
= 32/ 3125
3a. 1^99 - 0. 6^2
= 1 - 0. 36
= 0. 64
3b. (0. 2 ) ^1 × (1/8)^2
= 0. 2 × 1/64
= 0. 2 × 0. 016
= 0. 0031
4a. (1/2)^2/ (5/8)^1
= 
Take the inverse of the denominator
=
× 
= 2/5
4b. 7^2 - 0. 5^3
= 49 - 0. 125
= 48. 875
5a. 3^1 - 0. 8 ^2
= 3 - 0. 64
= 2. 36
5b. 0. 7^2 + 0. 9^1
= 0. 49 + 0. 9
= 1. 39
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