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Mashcka [7]
3 years ago
7

Alonzo and Mitra wanted to share a pizza. Mitra ate

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer: 2/4 more pizzia

Step-by-step explanation: Becuse if Mirtra ate 1/4 of the pizzia then you have 3/4 left and alonzo ate 3/4 of the pizza and if you subtract those the differce ends up to be 2/4.

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Solve y+4x=12 3y=8-12x
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6 0
3 years ago
Which is bigger 0.21, 21%
andrew11 [14]
21% is bigger than 0.21
5 0
3 years ago
Read 2 more answers
Learning Task II. Illustrate the following: Illustration Given 1. Line Segment MN 2. Ray XY 3. Ray YX 4. Angle ABC 5. LK​
Mashutka [201]

The illustration of the given mathematical elements is as in the attached images.

<h3>Illustration of mathematical elements</h3>

For line segments;

  • The beginning and end of the line are specified by the assigned alphabets.

However, for rays;

  • The ray is illustrated to originate from a point and span on from there till infinity.

For angles;

  • The alphabet in the middle of the set of 3 alphabets used to identify the angle represents the center point of where the angle is located.

Read more on illustration of mathematical elements;

brainly.com/question/18430725

6 0
2 years ago
Need help with this problem
icang [17]
Okay we'll start easy
46*93
We will take 6*3 which is 18.
40*3 which is 120
6*90 which is 540
40*90 which is 3600
Now add up those 
18+120+540+3600 which is 4278

So the missing numbers.

3._00 is going to be 3600
5_0 is going to be 540
_20 is going to be 120
1_ is going to be 18
4._78 is going to be 4.278
Hope this helped. ^~^
6 0
3 years ago
Please answer quickly
ValentinkaMS [17]

1a. 10. 24

1b. 125/243

2a. 0. 0048

2b. 32/3125

3a. 0. 64

3b. 0. 0031

4a. 2/5

4b. 48. 735

5a. 2. 36

5b. 1. 39

<h3>How to determine the values</h3>

1a. Given the values

(2/5)^2/(1/2)^6

Multiply both the numerator and denominator by the powers

⇒ \frac{\frac{4}{25} }{\frac{1}{64} }

To find the common ration, multiply thus;

⇒ \frac{4}{25}<em> × </em>\frac{64}{1}

⇒ \frac{256}{25}

= 10. 24

1b. (5/7)^2 × (5/7)^1

= \frac{25}{49} × \frac{5}{7}

= \frac{125}{343}

= 125/243

2a. 0. 6^1  × 0. 2^3

= 0. 6 × 0. 008

= 0. 0048

2b. (2/5)^3 × (2/5)^2

= \frac{8}{125} × \frac{4}{25}

<em>= </em>\frac{32}{3125}

= 32/ 3125

3a. 1^99 - 0. 6^2

= 1 - 0. 36

= 0. 64

3b. (0. 2 ) ^1 × (1/8)^2

= 0. 2 × 1/64

= 0. 2 × 0. 016

= 0. 0031

4a. (1/2)^2/ (5/8)^1

= \frac{\frac{1}{4} }{\frac{5}{8} }

Take the inverse of the denominator

= \frac{1}{4} × \frac{8}{5}

= 2/5

4b. 7^2 - 0. 5^3

= 49 - 0. 125

= 48. 875

5a. 3^1 - 0. 8 ^2

= 3 - 0. 64

= 2. 36

5b. 0. 7^2 + 0. 9^1

= 0. 49 + 0. 9

= 1. 39

Learn more about index notation here:

brainly.com/question/10339517

#SPJ1

4 0
1 year ago
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